lightoj--1294--Largest Box(三分)】的更多相关文章

链接: https://vjudge.net/problem/LightOJ-1297 题意: In the following figure you can see a rectangular card. The width of the card is W and length of the card is L and thickness is zero. Four (x*x) squares are cut from the four corners of the card shown b…
题目链接:https://vjudge.net/contest/28079#problem/K 题目大意:给你一个长为L,宽为W的纸片,四个角剪掉边长为x的正方形,如下图所示,然后折成一个无盖的纸盒,求纸盒最大体积. 解题思路:我们可以知道体积V(x)=(L-2*x)*(W-2*x)*x求导得到f(x)=12x^2-4*(L+W)*x^2+L*W,V(x)的图像如下所示 所以我们知道极大值点是f(x)两个(或一个)零点中x值较小的那个点,可以通过求根公式求得. 代码: #include<iost…
1297 - Largest Box   PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB In the following figure you can see a rectangular card. The width of the card is W and length of the card is L and thickness is zero. Four (x*x) squares a…
1297 - Largest Box   PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB In the following figure you can see a rectangular card. The width of the card is W and length of the card is L and thickness is zero. Four (x*x) squares a…
链接: https://vjudge.net/problem/LightOJ-1294 题意: Given two integers: n and m and n is divisible by 2m, you have to write down the first n natural numbers in the following form. At first take first m integers and make their sign negative, then take nex…
传送门:Largest Box 题意:长度为L宽度为W的纸四个角去掉x*x的正方形,然后形成一个长方体,问能组成长方体的最大体积为多少. 分析:三分x求最值. #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #define N 100010 #define mod 1000000007 #define LL long long #define lson l,…
Largest Box Time Limit: 2000MS   Memory Limit: 32768KB   64bit IO Format: %lld & %llu Submit Status Description In the following figure you can see a rectangular card. The width of the card is W and length of the card is L and thickness is zero. Four…
题目链接:uva 1463 - Largest Empty Circle on a Segment 二分半径,对于每一个半径,用三分求出线段到线段的最短距离,依据最短距离能够确定当前R下每条线段在[0,L]上的可行区间,存在一个点被可行区间覆盖n次. #include <cstdio> #include <cstring> #include <cmath> #include <vector> #include <algorithm> using…
本身很容易却因为评测机有毒的一道题,,,看网上题解说最后一个答案要加一个很小的数才能AC,据说是因为没有speci judge #include <iostream> #include <string.h> #include <cstdio> #include <math.h> #define SIGMA_SIZE 26 #pragma warning ( disable : 4996 ) using namespace std; inline int Ma…
The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 710    Accepted Submission(s): 290 Problem Description There are N points in total. Every point moves in certain direction and…