我现在在做一个叫<leetbook>的开源书项目,把解题思路都同步更新到github上了,需要的同学可以去看看 这个是书的地址: https://hk029.gitbooks.io/leetbook/ 19. Remove Nth Node From End of List 问题 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked…

Remove Nth Node From End of List Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes…

一天一道LeetCode系列 (一)题目 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->…

https://leetcode.com/problems/remove-nth-node-from-end-of-list/ 原题: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node fro…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:链表, 删除节点,双指针,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 双指针 日期 题目地址:https://leetcode.com/problems/remove-nth-node-from-end-of-list/description/ 题目描述 Given a linked list,…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 38: Count and Sayhttps://oj.leetcode.com/problems/count-and-say/ The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ... 1 is read off as "o…

1. 原题链接 https://leetcode.com/problems/remove-nth-node-from-end-of-list/description/ 2. 题目要求 给出一个链表,请删除倒数第n个结点并返回头节点 注意:给出的n总在合法范围内:只用一次遍历: 3. 解题思路 删除倒数第n个结点,正着数即删除从表头结点开始的第L-n+1个结点.创建一个表头结点来指向头结点. 思路一:使用两次遍历.第一次遍历得到链表的长度,第二遍历删除第L-n+1个结点. 思路二:使用一次遍历.使…

题目: 思路:如果链表为空或者n小于1,直接返回即可,否则,让链表从头走到尾,每移动一步,让n减1. 1.链表1->2->3,n=4,不存在倒数第四个节点,返回整个链表 扫过的节点依次:1-2-3 n值得变化:3-2-1 2.链表1->2->3,n=3 扫过的节点依次:1-2-3 n值得变化:2-1-0 3.链表1->2->3,n=2 扫过的节点依次:1-2-3 n值得变化:1-0--1 当走到链表结尾时:1.n>0,说明链表根本没有第n个节点,直接返回原链表:…

61. Rotate List(M) Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given ->->->->->NULL and k = , ->->->->->NULL. Total Accepted: 102574 Total Submissions: 423333 Difficulty: Medi…