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Alexandra and Prime Numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1658    Accepted Submission(s): 565 Problem Description Alexandra has a little brother. He is new to programming. One…
题意: 给一个正整数N,找最小的M,使得N可以整除M,且N/M是质数. 数据范围: There are multiple test cases (no more than 1,000). Each case contains only one positive integer N.N≤1,000,000,000.Number of cases with N>1,000,000 is no more than 100. 思路: N=M*prime     故必有M或prime小于等于sqrt(N)…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5108 题目意思:给出一个数正整数 N,N <= 1e9,现在需要找出一个最少的正整数 M,使得 N/M 是素数.如果找不到就输出0. 一开始有想过将所有 <= 1e9 的素数求出来的,不过绝对超时就放弃了:然后就开始从题目中挖掘简便的处理方法.受到求素数的方法启发,枚举的因子 i 如果在 i * i <= N 之内都没有找到符合条件的素数,那么那些 > N 的因子就更不可能了.于是时间…
数论题,本质是求出n的最大质因子 #include<time.h> #include <cstdio> #include <iostream> #include<algorithm> #include<math.h> #include <string.h> #include<vector> #include<queue> using namespace std; int main() { int n,t; wh…
Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20050   Accepted: 10989 Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representatio…
题目链接: 传送门 Sum of Consecutive Prime Numbers Time Limit: 1000MS     Memory Limit: 65536K Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representations does a given positive intege…
Sieve of Eratosthenes (素数筛选算法) Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number. For example, if n is 10, the output should be “2, 3, 5, 7″. If n is 20, the output should be “2, 3, 5, 7, 11, 13,…
Problem Description Give you a lot of positive integers, just to find out how many prime numbers there are. Input There are a lot of cases. In each case, there is an integer N representing the number of integers to find. Each integer won't exceed 32-…
题目链接:Codeforces 385C Bear and Prime Numbers 这题告诉我仅仅有询问没有更新通常是不用线段树的.或者说还有比线段树更简单的方法. 用一个sum数组记录前n项和,这个sum数组在打素数表时候就能够求出来,注意一点求素数的内层循环要改成i.不能再写成i + i或者i * i了.原因想想就明确了. 这学期最后一场比赛也结束了,结果不非常惬意但也还好. 总的来说这学收获还是蛮多的. 近期可能就不再做ACM了吧,可能要复习CET6了吧,可能要复习期末考试的内容了吧.…
POJ2739 Sum of Consecutive Prime Numbers 题目大意:给出一个整数,如果有一段连续的素数之和等于该数,即满足要求,求出这种连续的素数的个数 水题:艾氏筛法打表+尺取法区间推进,0ms水过(注意循环的终止条件) #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <ctime> #include &l…