Problem Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:w(20, 20, 20)…

Problem Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:w(20, 20, 20)…

洛谷P1464 Function HDU P1579 Function Run Fun 题目描述 对于一个递归函数w(a,b,c) 如果a≤0 or b≤0 or c≤0就返回值11. 如果a>20 or b>20 or c>20 就返回w(20,20,20 如果a<b并且b<c 就返回w(a,b,c-1)+w(a,b-1,c-1)-w(a,b-1,c) 其它的情况就返回w(a-1,b,c)+w(a-1,b-1,c)+w(a-1,b,c-1)-w(a-1,b-1,c-1) 这…

HDU 5608 function 题意:数论函数满足\(N^2-3N+2=\sum_{d|N} f(d)\),求前缀和 裸题-连卷上\(1\)都告诉你了 预处理\(S(n)\)的话反演一下用枚举倍数的方法 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; typed…

HDU 5608 - function 套路题 图片来自: https://blog.csdn.net/V5ZSQ/article/details/52116285 杜教筛思想,根号递归下去. 先搞出前缀和g(n)=∑f(i) 然后寻求递归.∑g(n/i)=常数 这一步要运用给出的f(i)的关系,干掉f 具体: 向枚举约数转化,不断交换求和,交换统计贡献的部分.通过数学意义变成枚举约数 然后类似杜教筛即可 f的前1000000项,调和级数枚举约数减去贡献 #include<bits/stdc++…

题目传送门:http://poj.org/problem?id=1579 Function Run Fun Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 20560   Accepted: 10325 Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <=…

Function Run Fun Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2586    Accepted Submission(s): 1255 Problem Description We all love recursion! Don't we? Consider a three-parameter recursive f…

/* HDU 6038 - Function [ 置换,构图 ] 题意: 给出两组排列 a[], b[] 问 满足 f(i) = b[f(a[i])] 的 f 的数目 分析: 假设 a[] = {2, 0, 1} 则 f(0) = b[f(2)] f(1) = b[f(0)] f(2) = b[f(1)] 即 f(0) = b[b[b[f(0)]]] f(1) = b[b[b[f(1)]]] f(2) = b[b[b[f(2)]]] 由于将 a[i]->i 连边可以得到不相交的多个循环 可以看出…

版权声明:本文为博主原创文章.未经博主同意不得转载.vasttian https://blog.csdn.net/u012860063/article/details/37076755 转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents 题目链接:pid=1579" rel="nofollow">http://acm.hdu.edu.cn/showproblem.php? pid=1579 Problem…

Function Time Limit: 7000/3500 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 976    Accepted Submission(s): 375 Problem Description The shorter, the simpler. With this problem, you should be convinced of this tru…