Java-POJ1003-Hangover - 相关文章

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[POJ1003]Hangover

[POJ1003]Hangover 试题描述 How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can m…

POJ1003 – Hangover (基础)

Hangover Description How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can m…

POJ-1003&1004

这两题比较简单,就不做分析了,描述下题目,就上代码吧. [题目描述] 1003,其实就是求这个方程的最小n:1/2 + 1/3 + 1/4 + ... + 1/(n + 1) >= c: 1004,其实就是算个平均数,直接除12 [附:完整代码] 1003题: /* POJ-1003 Hangover */ #include <iostream> using namespace std; int main() { double c; while(cin>>c) { if (c…

Spark案例分析

一.需求:计算网页访问量前三名 import org.apache.spark.rdd.RDD import org.apache.spark.{SparkConf, SparkContext} /** * 需求:计算网页访问量前三名 * 用户:喜欢视频直播 * 帮助企业做经营和决策 * * 看数据 */ object UrlCount { def main(args: Array[String]): Unit = { //1.加载数据 val conf:SparkConf = new Spa…

Hangover[POJ1003]

Hangover Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 121079 Accepted: 59223 Description How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're a…

【POJ1003】Hangover（二分搜索）

直接用库函数二分即可. #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <cctype> #include <algorithm> #include <numeric> #define eps 1e-8 using namespace std; ]; int…

POJ题目排序的Java程序

POJ 排序的思想就是根据选取范围的题目的totalSubmittedNumber和totalAcceptedNumber计算一个avgAcceptRate. 每一道题都有一个value,value = acceptedNumber / avgAcceptRate + submittedNumber. 这里用到avgAcceptedRate的原因是考虑到通过的数量站的权重可能比提交的数量占更大的权重,所以给acceptedNumber乘上了一个因子. 当然计算value还有别的方法,比如POJ上…