Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 难度:95,参考了网上的思路.这道题是树中比较有难度的题目,需要根据先序遍历和中序遍历来构造出树来.这道题看似毫无头绪,其实梳理一下还是有章可循的.下面我们就用一个例子来解释如何构造出树.假设树的先序遍历是12453687,…

Construct Binary Tree from Preorder and Inorder Traversal Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. SOLUTION 1: 1. Find the root node from the preorder.(it…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 这道题要求用先序和中序遍历来建立二叉树,跟之前那道Construct Binary Tree from Inorder and Postorder Traversal 由中序和后序遍历建立二叉树原理基本相同,针对这道题,由于先…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 此题目有两种解决思路: 1)递归解决(比较好想)按照手动模拟的思路即可 2)非递归解决,用stack模拟递归 class Solution { public: TreeNode *buildTree(vector<int>&…

原题地址:http://oj.leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/ 题意:根据二叉树的先序遍历和中序遍历恢复二叉树. 解题思路:可以参照 http://www.cnblogs.com/zuoyuan/p/3720138.html 的思路.递归进行解决. 代码: # Definition for a binary tree node # class TreeNode: # d…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:  You may assume that duplicates do not exist in the tree. 利用前序和中序遍历构造二叉树的思想与利用中序和后续遍历的思想一样,不同的是,全树的根节点为preorder数组的第一个元素,具体分析过程参照利用中序和后续构造二叉树.这两道题是从二叉树的前序遍历.中序遍历.后续遍历这三种遍…

Question Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. Solution 参考:http://www.cnblogs.com/zhonghuasong/p/7096150.html Code /** * Definition for a binary tree…

Question: Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. Analysis: 给出一棵树的前序遍历和中序遍历,构建这棵二叉树. 注意: 你可以假设树中不存在重复的关键码.   思路: 前序遍历和中序遍历肯定是可以唯一确定一棵二叉树的.  前序遍历的第一个节点肯定是…

总结: 1. 第 36 行代码, 最好是按照 len 来遍历, 而不是下标 代码: 前序中序 #include <iostream> #include <vector> using namespace std; struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { publ…

LeetCode:Construct Binary Tree from Inorder and Postorder Traversal Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree.                                            …