You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…

把pattern映射到数字,也就是把pattern标准化. 比如abb和cdd如果都能标准化为011,那么就是同构的. class Solution: def findAndReplacePattern(self, words: List[str], pattern: str) -> List[str]: p = self.get_pattern(pattern) ans = [] for w in words: if self.get_pattern(w) == p: ans.append(w…

Question 890. Find and Replace Pattern Solution 题目大意:从字符串数组中找到类型匹配的如xyy,xxx 思路: 举例:words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb" abb -> 011 abc -> 012 deq -> 0…

You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典+set 单字典 日期 题目地址:https://leetcode.com/problems/find-and-replace-pattern/description/ 题目描述 You have a list of words and a pattern, and you want to know which words in words ma…

［抄题］: You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get…

You have a list of words and a pattern, and you want to know which words in words matches the pattern. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the d…

这是悦乐书的第236次更新,第249篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第103题(顺位题号是459).给定非空字符串检查是否可以通过获取它的子字符串并将子字符串的多个副本附加在一起来构造它. 您可以假设给定的字符串仅由小写英文字母组成,其长度不超过10000.例如: 输入:"abab" 输出:true 说明:它是子串"ab"两次. 输入:"aba" 输出:false 输入:"abcabcabca…

290. 单词规律 290. Word Pattern 题目描述 给定一种规律 pattern 和一个字符串 str,判断 str 是否遵循相同的规律. 这里的 遵循 指完全匹配,例如,pattern 里的每个字母和字符串 str 中的每个非空单词之间存在着双向连接的对应规律. 每日一算法2019/6/13Day 41LeetCode290. Word Pattern 示例1: 输入: pattern = "abba", str = "dog cat cat dog"…

#-*- coding: UTF-8 -*-class Solution(object):    def wordPattern(self, pattern, str):        """        :type pattern: str        :type str: str        :rtype: bool        """        tag=0        tagdic={}        tagList=[]  …