Q1: Find the smallest value from array: function findMin(arr) { let min = arr[0]; for (let i = 1; i < arr.length; i++) { if (arr[i] < min) { min = arr[i]; } } } O(n), cannot be improved anymore, because we have to loop though the array once. Q2: Fin…

The trivial way, O(m + n): Merge both arrays and the k-th smallest element could be accessed directly. Merging would require extra space of O(m+n). The linear run time is pretty good, but could we improve it even further? A better way, O(k): There is…

题目链接:点击传送 D. Powerful array time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output An array of positive integers a1, a2, ..., an is given. Let us consider its arbitrary subarray al, al + 1..., ar…

When I had the requirement to remove duplicate items from a very large array, I found out that the classic method to be not optimized as it took a pretty long time than desired. So, I devised this new algorithm that can sort a large array in a fracti…

Bubble sort Bubble sort, sometimes incorrectly referred to as sinking sort, is a simple sorting algorithm that works by repeatedly stepping through the list to be sorted, comparing each pair of adjacent items and swapping them if they are in the wron…

reference is_permutation Test whether range is permutation of another Parameters first1, last1 Input iterators to the initial and final positions of the first sequence. The range used is [first1,last1), which contains all the elements between first1…

先贴一段C++标准(ISO/IEC 14882:2003): 5.2.1 Subscripting: 1 A postfix expression followed by an expression in square brackets is a postfix expression. One of theexpressions shall have the type “pointer to T” and the other shall have enumeration or integral…

一.字典序法 1) 从序列P的右端开始向左扫描,直至找到第一个比其右边数字小的数字,即. 2) 从右边找出所有比大的数中最小的数字,即. 3) 交换与. 4) 将右边的序列翻转,即可得到字典序的下一个排列. 5) 重复上面的步骤,直至得到字典序最大的排列,即左边数字比右边的大的降序排列. //字典序法 void dictionary(int length){ int * data = (int *)malloc(sizeof(int) * length); int index; for (ind…

MSS(Array[],N)//Where N is the number of elements in array { sum=; //current sum max-sum=;//Maximum Sum seq-start=;//start of the subsequence seq-end=;//end of the subsequence ;i<N;i++){ sum=sum+Array[i]; ){ sum=; seq-start++; } else{ if(sum>max-sum…

http://codeforces.com/problemset/problem/949/B Dima is a beginner programmer. During his working process, he regularly has to repeat the following operation again and again: to remove every second element from the array. One day he has been bored wit…