Leetcode1--两数之和 题目分类:数组.哈希表的应用 1. 题目描述 给定一个整数数组 nums 和一个整数目标值 target,请你在该数组中找出 和为目标值 target 的那 两个 整数,并返回它们的数组下标. 你可以假设每种输入只会对应一个答案.但是,数组中同一个元素在答案里不能重复出现. 你可以按任意顺序返回答案.(原题网址:https://leetcode-cn.com/problems/two-sum/) 示例1: 输入:nums = [2,7,11,15], target…

/** * Definition for a binary tree node. * struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * }; */ #define MAX 1000 int Path[MAX]; int index1; int power(int x,int n){ int i,re; if(n==0)return 1; for(i=0,re=1;i<n;++i){…

题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note t…

package java_net_test; import java.util.HashMap; import java.util.Iterator; import java.util.Map; public class twoSum { public static void main(String[] args) { // TODO Auto-generated method stub int target=9; int[] num={2,7,11,15}; int[]res; for(int…

题目 :Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution.  (Easy) 解法1: Two pointers 拷贝一份,将数组排序,两根指针分别从前后向中间扫描,找到解为止.再遍历原数组寻找下标添加到结果内.…

 问题描写叙述:在一个数组(无序)中高速找出两个数字,使得两个数字之和等于一个给定的值.如果数组中肯定存在至少一组满足要求. <剑指Offer>P214(有序数组) <编程之美>P176 Que:Given an array of integers, find twonumbers such that they add up to a specific target number. The function twoSum should return indices ofthe…

题目描述: 给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的那 两个 整数,并返回他们的数组下标. 你可以假设每种输入只会对应一个答案.但是,你不能重复利用这个数组中同样的元素. 示例: 给定 nums = [2, 7, 11, 15], target = 9 因为 nums[0] + nums[1] = 2 + 7 = 9 所以返回 [0, 1] 方法一: public static int[] twoSum(int[] nums, int target)…

Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15]…

给定一个整数数组和一个目标值,找出数组中和为目标值的两个数. 你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用. 实例: 给定 nums = [2, 7, 11, 15],target = 9 因为 nums[0] + nums[1] = 2 + 7 = 9 所以返回 [0, 1] 1.我的思路: 可以提交但时间复杂度为O(n^2).其中13到20行为了解决数组里有重复元素时,不能用index的情况.如图 class Solution: def twoSum(self, nums,…

public class Solution { public int[] TwoSum(int[] nums, int target) { ]; ; i < nums.Length; i++) { ; j < nums.Length; j++) { if (nums[i] + nums[j] == target) { ary[] = i; ary[] = j; return ary; } } } return ary; } } https://leetcode.com/problems/two…