poj 2769 Reduced ID Numbers 同余定理】的更多相关文章

链接:http://poj.org/problem?id=2769 题意:寻找数m,是的对于n个数的余数不同 思路:暴力,优化:同余部分不用测试 代码: #include <iostream> #include <string.h> using namespace std; ],vis[]; int main() { ios::sync_with_stdio(false); //freopen("in.txt","r",stdin); //f…
Description T. Chur teaches various groups of students at university U. Every U-student has a unique Student Identification Number (SIN). A SIN s is an integer in the range 0 ≤ s ≤ MaxSIN with MaxSIN = 106-1. T. Chur finds this range of SINs too larg…
id=1465">http://poj.org/problem?id=1465 Multiple Time Limit: 1000MS   Memory Limit: 32768K Total Submissions: 6164   Accepted: 1339 Description a program that, given a natural number N between 0 and 4999 (inclusively), and M distinct decimal digit…
Description T. Chur teaches various groups of students at university U. Every U-student has a unique Student Identification Number (SIN). A SIN s is an integer in the range 0 ≤ s ≤ MaxSIN with MaxSIN = 10 6-1. T. Chur finds this range of SINs too lar…
T. Chur teaches various groups of students at university U. Every U-student has a unique Student Identification Number (SIN). A SIN s is an integer in the range 0 ≤ s ≤ MaxSIN with MaxSIN = 10 6-1. T. Chur finds this range of SINs too large for ident…
The Embarrassed Cryptographer Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11978   Accepted: 3194 Description The young and very promising cryptographer Odd Even has implemented the security module of a large system with thousands of…
题目链接: http://poj.org/problem?id=1426 Description Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there…
The Embarrassed Cryptographer Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15767   Accepted: 4337 Description The young and very promising cryptographer Odd Even has implemented the security module of a large system with thousands of…
  http://poj.org/problem?id=1651Multiplication Puzzle   Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6188   Accepted: 3777 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer.…
http://poj.org/problem?id=1286 题意:有红.绿.蓝三种颜色的n个珠子.要把它们构成一个项链,问有多少种不同的方法.旋转和翻转后同样的属于同一种方法. polya计数. 搜了一篇论文Pólya原理及其应用看了看polya究竟是什么东东.它主要计算所有互异的组合的个数.对置换群还是似懂略懂.用polya定理解决这个问题的关键是找出置换群的个数及哪些置换群,每种置换的循环节数.像这样的不同颜色的珠子构成项链的问题能够把N个珠子看成正N边形. Polya定理:(1)设G是p…