Same Tree Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Maximum Depth of Binary Tree Given a binary tree, find i…

Binary Tree Level Order Traversal Total Accepted: 79463 Total Submissions: 259292 Difficulty: Easy Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3,…

遍历二叉树   traversing binary tree 线索二叉树 threaded binary tree 线索链表 线索化 1. 二叉树3个基本单元组成:根节点.左子树.右子树 以L.D.R分别表示遍历左子树.访问根节点.遍历右子树 可能的情况6种 排列A3 2 LDR LRD DLR DRL RLD RDL 若限定先左后右 LDR LRD  中根序遍历  后根序遍历 DLR  先根序遍历 先/中/后 序遍历…

一.Blend Tree介绍及应用 一个游戏动画的基本任务就是将两个或多个相似的动作混合.也许最广为人知的例子就是依照任务行动的速度将行走和跑动动画混合起来了.另一个例子就是角色在跑动中向左或向右转身. 如何创建Blend Tree: 在动画视窗中右键:Create State-From new Blend TreeBlendTree主要作用: 把几个类似的动画片段合成复合的动画片段,可以说相当于一个动画合成器.典型的应用: 想前跑.右跑.左跑类似的走动画片段,通过BlendTree可以把这三个…

$ ./out/target/product/project_name/obj/KERNEL_OBJ/scripts/dtc/dtc -I dtb -O dts -o decompiled.dts ~/project/linux_repo/out/target/product/project_name/obj/KERNEL_OBJ/arch/arm64/boot/dts/your.dtb 也就是 scripts/dtc/dtc -I dtb -O dts -o you_want.dts your…

Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 比较左子树和右子树的深度,取小的那个返回上来,并+1. 需要注意的是如果没有左子树或右子树.那么无条件取存在的那一边子树深…

LeetCode:Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 算法1:dfs递归的求解 class Solution { public: int minDepth(T…

Binary Tree Level Order Traversal OJ: https://oj.leetcode.com/problems/binary-tree-level-order-traversal/ Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary…

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Title: Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,…