【【LeetCode OJ】Convert Sorted Array to Binary Search Tree】的更多相关文章

【LeetCode OJ】Convert Sorted Array to Binary Search Tree

Problem Link: http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Same idea to Convert Sorted Array to Binary Search Tree, but we use a recursive function to construct the binary search tree. # Definition for a binary tree nod…

【LeetCode OJ】Convert Sorted List to Binary Search Tree

Problem Link: http://oj.leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ We design a auxilar function that convert a linked list to a node with following properties: The node is the mid-node of the linked list. The node's left child i…

LeetCode OJ 108. Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 把一个有序的数组转换为一颗平衡二叉搜索树.每次找到中间节点作为根节点,根节点左边部分转换为左子树,右边部分转换为右子树.代码如下: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNo…

LeetCode OJ：Convert Sorted Array to Binary Search Tree（将排序好的数组转换成二叉搜索树）

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 讲一个排序好的数组转换成二叉搜索树,这题没想出来,基本上是参考别人的,边界条件应该注意一下: /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *rig…

【leetcode】Convert Sorted Array to Binary Search Tree

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST.   每次把中间元素当成根节点,递归即可   /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * Tre…

Leetcode No.108 Convert Sorted Array to Binary Search Tree(c++实现）

1. 题目 1.1 英文题目 Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree. A height-balanced binary tree is a binary tree in which the depth of the two subtrees of every node never…

【leetcode】Convert Sorted Array to Binary Search Tree (easy)

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 有序数组变二叉平衡搜索树,不难,递归就行.每次先序建立根节点(取最中间的数),然后用子区间划分左右子树. 一次就AC了 注意:new 结构体的时候对于 struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x)…

【题解】【BST】【Leetcode】Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.思路:对于树来说,自顶向下的递归是很好控制的,自底向上的递归就很容易让脑神经打结了.本来想仿照排序二叉树的中序遍历,逆向地由数组构造树,后来发现这样做需要先确定树的结构,不然会一直递归下去,不知道左树何时停止.代码: TreeNode *addNode(vector<int> &num, int…

【Leetcode】【Medium】Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 用一个有序数组,创建一个平衡二叉查找树. 为确保平衡,需要满足两子树的高度差不大于1,可以通过设置左子树结点数等于或者比右子树结点数多1,来实现. 那么每次取数组的中间位置后一个值,作为根结点,数组左边元素的插入左子树,数组右边元素插入右子树,依次类推. 代码: /** * Definiti…

【leetcode刷题笔记】Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题解:递归就可以了. Java代码如下: /** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val =…