删除最小数目的无效括号,使输入的字符串有效,返回所有可能的结果.注意: 输入可能包含了除 ( 和 ) 以外的元素.示例 :"()())()" -> ["()()()", "(())()"]"(a)())()" -> ["(a)()()", "(a())()"]")(" -> [""]详见:https://leetcode.com/…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()"Output: ["()()(…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()…

［抄题］: Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: [&quo…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Examples: "()())()" -> ["()()()",…

题目: Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Examples: "()())()" -> ["()()()&quo…

原题链接在这里:https://leetcode.com/problems/remove-invalid-parentheses/ 题目: Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the par…

题目如下: 解题思路:还是这点经验,对于需要输出整个结果集的题目,对性能要求都不会太高.括号问题的解法也很简单,从头开始遍历输入字符串并对左右括号进行计数,其中出现右括号数量大于左括号数量的情况,表示这个区间是不合法的,需要删掉一个右括号:遍历完成后,如果左括号数量大于右括号的数量,那么需要删除左括号,直至两者相等. 代码如下: class Solution(object): def removeInvalidParentheses(self, s): """ :type s…

Leetcode之深度优先搜索(DFS)专题-301. 删除无效的括号(Remove Invalid Parentheses) 删除最小数量的无效括号,使得输入的字符串有效,返回所有可能的结果. 说明: 输入可能包含了除 ( 和 ) 以外的字符. 示例 1: 输入: "()())()" 输出: ["()()()", "(())()"] 示例 2: 输入: "(a)())()" 输出: ["(a)()()",…

删除无效的括号 删除最小数量的无效括号,使得输入的字符串有效,返回所有可能的结果. 说明: 输入可能包含了除 ( 和 ) 以外的字符. 示例 1: 输入: "()())()" 输出: ["()()()", "(())()"] 示例 2: 输入: "(a)())()" 输出: ["(a)()()", "(a())()"] 示例 3: 输入: ")(" 输出: [&quo…

301. 删除无效的括号 删除最小数量的无效括号,使得输入的字符串有效,返回所有可能的结果. 说明: 输入可能包含了除 ( 和 ) 以外的字符. 示例 1: 输入: "()())()" 输出: ["()()()", "(())()"] 示例 2: 输入: "(a)())()" 输出: ["(a)()()", "(a())()"] 示例 3: 输入: ")(" 输出:…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()…

题目 题解 step1. 遍历一遍,维护left.right计数器,分别记录不合法的左括号.右括号数量. 判断不合法的方法? left维护未匹配左括号数量(增,减)(当left为0遇到右括号,则交由right处理),最终剩余的左括号数量就是不合法的左括号数量 遇右括号时,若左侧的左括号都已被匹配(left==0),则此右括号为不合法右括号,right++ PS 对于题目中最少:此方法判断出的所有不合法括号,就是所谓的最少不合法括号数量:在此基础上得到的合理表达式,删除成对的括号,也会是合法表达式…

Question Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Examples: "()())()" -> ["()()(…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Examples: "()())()" -> ["()()()",…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()…

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Example 1: Input: "()())()" Output: ["()()…

网址:https://leetcode.com/problems/remove-outermost-parentheses/ 使用栈的思想,选择合适的判断时机 class Solution { public: string removeOuterParentheses(string S) { stack<char> s_ch; string ans; stack<char> temp; , r = ; ; i<S.size(); i++) { if(S[i] == '(')…

https://leetcode-cn.com/problems/remove-outermost-parentheses/ Java Solution class Solution { public String removeOuterParentheses(String S) { char[] chars = S.toCharArray(); int flag = 0; StringBuilder result = new StringBuilder(); for (char c : cha…

This problem can be solved very elegantly using BFS, as in this post. The code is rewritten below in C++. class Solution { public: vector<string> removeInvalidParentheses(string s) { vector<string> parens; queue<string> candidates; unord…

1021. 删除最外层的括号 1021. Remove Outermost Parentheses 题目描述 有效括号字符串为空 ("")."(" + A + ")" 或 A + B,其中 A 和 B 都是有效的括号字符串,+ 代表字符串的连接.例如,"","()","(())()" 和 "(()(()))" 都是有效的括号字符串. 如果有效字符串 S 非空,且不存在…

Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. For "(()", the longest valid parentheses substring is "()", which has length = 2. Another example is &…

Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. Example 1: Input: "(()" Output: 2 Explanation: The longest valid parentheses substring is "()" Example…

709. To Lower Case(Easy)# Implement function ToLowerCase() that has a string parameter str, and returns the same string in lowercase. Example 1: Input: "Hello" Output: "hello" Example 2: Input: "here" Output: "here"…

Sub 替换立方米() With Selection.Find .Text = "m3" .Replacement.Text = "mm3" .Forward = True .Wrap = wdFindContinue .Format = True .MatchCase = False .MatchWholeWord = False .MatchByte = False .MatchWildcards = False .MatchSoundsLike = False…

consul删除无效实例删除无效服务删除无效节点删除无效服务http://127.0.0.1:8500/v1/agent/service/deregister/test-9c14fa595ddfb8f4c34c673c65b072bb test-9c14fa595ddfb8f4c34c673c65b072bb : 实例idmethod : put 删除无效节点http://127.0.0.1:8500/v1/v1/agent/force-leave/4b36b27317a0 consul lea…

problem 1021. Remove Outermost Parentheses 参考 1. Leetcode_easy_1021. Remove Outermost Parentheses; 完…

A valid parentheses string is either empty (""), "(" + A + ")", or A + B, where A and B are valid parentheses strings, and +represents string concatenation.  For example, "", "()", "(())()", and …

这是小川的第380次更新,第408篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第242题(顺位题号是1021).有效的括号字符串为空(""),"("+ A +")"或A + B,其中A和B是有效的括号字符串,+表示字符串连接.例如,"","()","(())()"和"(()(()))"都是有效的括号字符串. 如果有效的括号字符串S是非空…

题目 给你一个由 '('.')' 和小写字母组成的字符串 s. 你需要从字符串中删除最少数目的 '(' 或者 ')' (可以删除任意位置的括号),使得剩下的「括号字符串」有效. 请返回任意一个合法字符串. 有效「括号字符串」应当符合以下 任意一条 要求: 空字符串或只包含小写字母的字符串 可以被写作 AB(A 连接 B)的字符串,其中 A 和 B 都是有效「括号字符串」 可以被写作 (A) 的字符串,其中 A 是一个有效的「括号字符串」 示例 1: 输入:s = "lee(t(c)o)de)&q…