Leetcode 44 实现一种类似正则表达式的字符串匹配功能. 复杂度要求不高, 调代码稍微费点劲.. 好像跟贪心也不太沾边, 总之 *把待匹配串分成若干个子串, 每一个子串尽量在模式串中靠前的部分匹配完成就算贪心了吧.. class Solution { public: bool match(string &s,string &p,int l2,int r2,int l1) { if(l2==r2)return true; if(l1+r2-l2-1>=s.length())re…

44. Wildcard Matching Problem's Link ---------------------------------------------------------------------------- Mean: 给你一个字符串和一个自动机,问你自动机可否接收这个字符串. analyse: 由于自动机的模式很简单,所以可以直接模拟. Time complexity: O(N) view code );        )            ;}/* */…

Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the enti…

Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the enti…

题目链接:https://leetcode.com/problems/wildcard-matching/?tab=Description   '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). 字符串匹配问题. 如上所示:其中 ‘ ?’ 可以匹配任何一个单字符    ’ * ‘ 可以匹配任意长度的字符包括空字符串  给定字符串s,和字符串…

搬运工了- - https://blog.csdn.net/jmspan/article/details/51460021…

10. Regular Expression Matching https://www.cnblogs.com/grandyang/p/4461713.html class Solution { public: bool isMatch(string s, string p) { if(p.empty()) return s.empty(); && p[] == '*') )) || (!s.empty() && (s[] == p[] || p[] == ),p)); e…

题目: Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The functi…

Wildcard Matching Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partia…

Wildcard Matching Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partia…