执行数据库查询时,有完整查询和模糊查询之分.一般模糊语句如下:SELECT 字段 FROM 表 WHERE 某字段 Like 条件 其中关于条件,SQL提供了四种匹配模式:1.%:表示任意0个或多个字符.可匹配任意类型和长度的字符,有些情况下若是中文,请运用两个百分号(%%)表示.比如 SELECT * FROM [user] WHERE u_name LIKE '%三%'将会把u_name为"张三","张猫三"."三脚猫","唐三藏&…
一.问题 用以下sql语句查询数据,结果为空 SELECT a.ID , a.Sub_Project_Name , a.Sub_Project_Type FROM TB_KYSubProject a WHERE a.ID NOT IN ( SELECT DISTINCT c.SubprojectID FROM TB_KYGrogramme c WHERE ISNULL(c.Belong_Programme, '') <> '' AND c.Belong_Programme IN ( SELEC…
在开发的过程中,遇到过not in 始终查询不到数据问题 select * from T_CustomerInfo where CustomerID not in (select CustomerID from T_OrderInfo) 后来使用not exists查询 select * from T_CustomerInfo a where not exists (select CustomerID from T_OrderInfo where CustomerID=a.CustomerID)…
我想实现类似如下sql语句的效果: select * from table1 where rw_id in ('7a482589-e52e-0887-4dd5-5821aab77eea','c68ace46-1c07-fccf-1cb6-57d4e77e40a2','3c9263d2-c44b-a9fd-155e-57aaf783ed58','69b087df-eb62-3e70-2cc0-582ec84a561b') 相应的ES查询应该写为: $v 即为 rw_id的集合,GET /_sear…