POJ 1568 Find the Winning Move】的更多相关文章

Find the Winning Move 链接 题意: 4*4的棋盘,给出一个初始局面,问先手有没有必胜策略? 有的话输出第一步下在哪里,如果有多个,按(0, 0), (0, 1), (0, 2), (0, 3), (1, 0), (1, 1) ... 的顺序输出第一个.没有输出“#####”. 分析: 极大极小搜索 或者 对抗搜索,α+β剪枝. 极大极小搜索:每个人都会进行最聪明的决策,假设有1号玩家为我们希望的玩家(即判断他能否有必胜的走法),那么对于一号玩家进行决策时,让他去所有后继状态…
题目链接:http://poj.org/problem?id=1568 题意:给出一个4*4的棋盘,x和o两人轮流放.先放够连续四个的赢.给定一个局面,下一个轮到x放.问x是否有必胜策略?若有,输出能够赢的最小的坐标? 思路:(1)Maxfind(Min):每次放x,若得到的Max大于等于Min,则直接返回Max.因为Minfind要用这个Max更新Min,若x放置之后能够得到一个比Min大的,显然这样放最好:因为Min无法用Max更新: (2)Minfind(Max)类似: (3)因此,枚举第…
思路:用极大极小搜索解决这样的问题很方便!! 代码如下: #include <cstdio> #include <algorithm> #define inf 100000000 using namespace std; ][]; int x,y,num; bool ok(int x,int y) //判断是否胜 { int i; ;i<;i++) //(x,y)所在的行 if(str[x][i]!=str[x][y]) break; ) ; ;i<;i++) //(x…
poj  1568:Find the Winning Move   [迭代博弈+搜索+剪枝] 题面省略... Input The input contains one or more test cases, followed by a line beginning with a dollar sign that signals the end of the file. Each test case begins with a line containing a question mark and…
Find the Winning Move Time Limit: 3000MS   Memory Limit: 32768K Total Submissions: 1286   Accepted: 626 Description 4x4 tic-tac-toe is played on a board with four rows (numbered 0 to 3 from top to bottom) and four columns (numbered 0 to 3 from left t…
http://poj.org/problem?id=1568 (题目链接) 题意 两人下4*4的井字棋,给出一个残局,问是否有先手必胜策略. Solution 极大极小搜索.. 这里有个强力优化,若已经被下了的的格子数cnt小于等于4的话,那么一定是平局至于为什么,自己YY一下发现好像是这样的.. 代码 // poj1568 #include<algorithm> #include<iostream> #include<cstring> #include<cstd…
Description 4x4 tic-tac-toe is played on a board with four rows (numbered 0 to 3 from top to bottom) and four columns (numbered 0 to 3 from left to right). There are two players, x and o, who move alternately with x always going first. The game is wo…
极小极大搜索 的个人理解(alpha-beta剪枝) 主要算法依据就是根据极大极小搜索实现的. 苦逼的是,查了两个晚上的错,原来最终是判断函数写错了..瞬间吐血! ps. 据说加一句 if sum < 4 printf("#####\n")会变态的快,不过懒得加了 ps. 1表示胜利,0表示平局,-1表示失败. #include <cstdio> #include <cstring> #include <iostream> #include &…
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  Nim Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4312   Accepted: 1998 Description Nim is a 2-player game featuring several piles of stones. Players alternate turns, and on his/her turn, a player’s move consists of removing one or m…