Codeforces Beta Round #10 D. LCIS】的更多相关文章

题目链接: http://www.codeforces.com/contest/10/problem/D D. LCIS time limit per test:1 secondmemory limit per test:256 megabytes 问题描述 This problem differs from one which was on the online contest. The sequence a1, a2, ..., an is called increasing, if ai …
D. LCIS 题目连接: http://www.codeforces.com/contest/10/problem/D Description This problem differs from one which was on the online contest. The sequence a1, a2, ..., an is called increasing, if ai < ai + 1 for i < n. The sequence s1, s2, ..., sk is call…
D. LCIS time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output This problem differs from one which was on the online contest. The sequence a1, a2, ..., an is called increasing, if ai < ai + 1 for …
C. Digital Root 题目连接: http://www.codeforces.com/contest/10/problem/C Description Not long ago Billy came across such a problem, where there were given three natural numbers A, B and C from the range [1, N], and it was asked to check whether the equat…
B. Cinema Cashier 题目连接: http://www.codeforces.com/contest/10/problem/B Description All cinema halls in Berland are rectangles with K rows of K seats each, and K is an odd number. Rows and seats are numbered from 1 to K. For safety reasons people, who…
A. Power Consumption Calculation 题目连接: http://www.codeforces.com/contest/10/problem/A Description Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes P1 watt per minute. T1 minute…
题目大意: n波人去k*k的电影院看电影. 要尽量往中间坐,往前坐. 直接枚举,贪心,能坐就坐,坐在离中心近期的地方. #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #define maxn 1000005 #define lowbit(x) (x&(-x)) using namespace std; struct BIT { int sum…
Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一个queen了,问你有多少种方案,能够得到n点 题解 其实只用考虑三种情况,都考虑一下就好了,实在不行就暴力枚举-- 代码 #include<bits/stdc++.h> using namespace std; int n; int main() { scanf("%d",&…
题目大意 给一个数列,长度不超过 5000,每次可以将其中的一个数加 1 或者减 1,问,最少需要多少次操作,才能使得这个数列单调不降 数列中每个数为 -109-109 中的一个数 做法分析 先这样考虑:如果操作的次数最少,那么最终得到的不降的数列,必然是由原始数列中的数组成的,具体的证明可以使用反证法 知道了上面讲述的性质,这题就好搞了 先将原始数列(设为 A,共 n 个数)中所有的数去重并从小到达排序,保存在另一个数列中(设为 B,共 m 个数) 定义状态:f[i][j] 表示将原始数列中的…
layout: post title: Codeforces Beta Round 84 (Div. 2 Only) author: "luowentaoaa" catalog: true tags: mathjax: true - codeforces 传送门 不得不说这远古场太简单了 A - Nearly Lucky Number (签到) 题意 给出一个数字 求其中7和4的数目是否是7和4组成 #include<bits/stdc++.h> using namespa…