一道来自jhu algorithm的作业题: Given two sorted arrays A, B, give a linear time algorithm that finds two entries i,j such that|A[i]−B[j]|is minimized. Prove the correctness of your algorithm and analyze the running time. Solution:我们可以对于每个a[i],然后再B数组中二分查找距离a[i…

From: http://blog.jobbole.com/73517/ 二分检索是查找有序数组最简单然而最有效的算法之一.现在的问题是,更复杂的算法能不能做的更好?我们先看一下其他方法. 有些情况下,散列整个数据集是不可行的,或者要求既查找位置,又查找数据本身.这个时候,用哈希表就不能实现O(1)的运行时间了.但对有序数组, 采用分治法通常可以实现O(log(n))的最坏运行时间. 在下结论前,有一点值得注意,那就是可以从很多方面“击败”一个算法:所需的空间,所需的运行时间,对底层数据结构的访…

(binary search trees) which form the basis of modern databases and immutable data structures. Binary search works very much the way humans intuitively search for a name in a yellow pages directory (if you have ever seen one) or the dictionary. In thi…

Complexity: O(log(n)) Ref: Binary search algorithm or 二分搜索算法 Ref: C 版本 while 循环 C Language scripts by McDelfino: #include <stdio.h> #include <stdlib.h> int getIndex(int* arr, int length, int num); int main() { int arr[100]; for (int i = 0; i &…

js binary search algorithm js 二分查找算法 二分查找, 前置条件 存储在数组中 有序排列 理想条件: 数组是递增排列,数组中的元素互不相同; 重排 & 去重 顺序: 递增排列/递减排列; 重复: 数组中存在相同的元素; "use strict"; /** * * @author xgqfrms * @license MIT * @copyright xgqfrms * @created 2020-05-20 * @modified * * @des…

38. Search a 2D Matrix II https://www.lintcode.com/problem/search-a-2d-matrix-ii/description?_from=ladder&&fromId=1 这道题与二分法有什么关系呢? -把整个二维数组从对角线分成两半,从左下角开始,往右上角逼近. public class Solution { /** * @param matrix: A list of lists of integers * @param ta…

254. Drop Eggs https://www.lintcode.com/problem/drop-eggs/description?_from=ladder&&fromId=1 28. Search a 2D Matrix https://www.lintcode.com/problem/search-a-2d-matrix/description?_from=ladder&&fromId=1 思路1: 1. find the row index, the last…

The solution for the problem can be divided into three cases: case 1: if the delete node is leaf node, then we can simply remove it case 2: if the delete node is has single side or substree case 3: it has two children, then to keep it as a valid bina…

What is Binary Search Tree (BST) A binary tree in which for each node, value of all the nodes in left subtree is less or equal and value of all the nodes in right subtree is greater The idea: We can use set boundry for each node. We take C tree for e…

Let's say we are going to find out number of occurrences of a number in a sorted array using binary search in O(log n) time. For example the given array is: [1,1,3,5,5,5,5,5,9,11], the number 5 appears 5 times; the number 3 appears 1 time; 2 appears…