Description A histogram is a polygon composed of a sequence of rectangles aligned at a common base line. The rectangles have equal widths but may have different heights. For example, the figure on the left shows the histogram that consists of rectang…

E - Largest Rectangle in a Histogram Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1506 Appoint description: Description A histogram is a polygon composed of a sequence of rectangles aligned a…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1506 题目: Largest Rectangle in a Histogram Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18833    Accepted Submission(s): 5636 Problem Description…

Largest Rectangle in a Histogram Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11137    Accepted Submission(s): 3047 Problem Description A histogram is a polygon composed of a sequence of rec…

Largest Rectangle in a Histogram Problem Description: A histogram is a polygon composed of a sequence of rectangles aligned at a common base line. The rectangles have equal widths but may have different heights. For example, the figure on the left sh…

题目链接:HDU - 1506 A histogram is a polygon composed of a sequence of rectangles aligned at a common base line. The rectangles have equal widths but may have different heights. For example, the figure on the left shows the histogram that consists of rec…

Largest Rectangle in a Histogram Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11706    Accepted Submission(s): 3219 Problem Description A histogram is a polygon composed of a sequence of rec…

                                                                                                   Largest Rectangle in a Histogram       A histogram is a polygon composed of a sequence of rectangles aligned at a common base line. The rectangles have…

单调栈和队列讲解:传送门 HDU -1506题意: 就是给你一些矩形的高度,让你统计由这些矩形构成的那个矩形面积最大 如上图所示,如果题目给出的全部是递增的,那么就可以用贪心来解决 从左向右依次让每一个矩形的高度当作最后的高度,来从中选取最大值就可以了 但是如果它不是递增的,中间会出现低谷,那么要还想运用贪心策略就要把之前高度大于它的全部扔掉,但是再扔掉他们之前还要判断一下以他们为最后答案的高度可不可行,这样我们就是在构造一个递增序列,可以用栈来维护它 代码: 1 #include<stdio.…

题意:坐标轴上有连续的n个底均为1,高为h[i]的矩形,求能够构成的最大矩形的面积. 学习的别人的代码 @_@ 看底的坐标怎么找的看了好一会儿--- 记l[i]为矩形的底的左边的坐标,就将它一直向左扩展 记r[i]为矩形的底的右边的坐标(倒着找,从n开始找,题解里面还着重强调了要倒着找,要不然就体现不出优化了)至于那个优化,我想的是,每一次算r[i]的时候,它前面的一个r[i]就是覆盖得最远的了,可以减少计算(用了一组样例试验) 然后就枚举找出面积的最大值-- #include<iostream…