LeetCode OJ 152. Maximum Product Subarray】的更多相关文章

Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. [题目分析] 给定一个整数数组,找出数组中的一个子序列,使得序列中所有元素的乘积最大…
Maximum Product Subarray Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Ex…
This a task that asks u to compute the maximum product from a continue subarray. However, you need to watch out the values' type contains positive, negative, zero. I solved it using dynamic process in which there are two arrays to achieve the goal. m…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双重循环 动态规划 参考资料 日期 题目地址:https://leetcode.com/problems/maximum-product-subarray/description/ 题目描述 Given an integer array nums, find the contiguous subarray within an array (conta…
题目: Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product = 6. 提示: 这道题可以使用动态规划求解,但是由于是乘法运算,所以情况更加复杂.…
Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4],the contiguous subarray [2,3] has the largest product = 6. 很显然是一个动态规划的问题,找到递归表达式就可以了,考虑到会有负负相乘的问题,所以应…
53. Maximum Subarray 之前的值小于0就不加了.dp[i]表示以i结尾当前的最大和,所以需要用一个变量保存最大值. 动态规划的方法: class Solution { public: int maxSubArray(vector<int>& nums) { vector<int> dp(nums.size()); int res = INT_MIN; ;i < nums.size();i++){ dp[i] = nums[i]; &&…
Question 152. Maximum Product Subarray Solution 题目大意:求数列中连续子序列的最大连乘积 思路:动态规划实现,现在动态规划理解的还不透,照着公式往上套的,这个问题要注意正负,需要维护两个结果 Java实现: public int maxProduct(int[] nums) { if (nums.length == 1) return nums[0]; // 定义问题:状态及对状态的定义 // 设max[i]表示数列中第i项结尾的连续子序列的最大连…
题目链接:Maximum Product Subarray solutions同步在github 题目很简单,给一个数组,求一个连续的子数组,使得数组元素之积最大.这是求连续最大子序列和的加强版,我们可以先看看求连续最大子序列和的题目maximum-subarray,这题不难,我们举个例子. 假设数组[1, 2, -4, 5, -1, 10],前两个相加后得到3,更新最大值(为3),然后再加上-4后,和变成-1了,这时我们发现如果-1去加上5,不如舍弃前面相加的sum,5单独重新开始继续往后相加…
Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1]…