1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 198  Solved: 118[Submit][Status][Discuss] Description It's election time. The farm is partitioned into a 5x5 grid of cow locations, each of which hold…

1675: [Usaco2005 Feb]Rigging the Bovine Election 竞选划区 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 196  Solved: 116[Submit][Status][Discuss] Description It's election time. The farm is partitioned into a 5x5 grid of cow locations, each of which hold…

http://www.lydsy.com/JudgeOnline/problem.php?id=1675 一开始我写了个枚举7个点....... 但是貌似... 写挫了. 然后我就写dfs.. 判重好难写啊. .... 本来用hash的.. 但是对拍一直wa.. 所以干脆用set.. 然后将数值调大.. 然后就过了.. 然后bzoj数据弱.. 自己对拍还是hash有冲突的.. #include <cstdio> #include <cstring> #include <cma…

Description It's election time. The farm is partitioned into a 5x5 grid of cow locations, each of which holds either a Holstein ('H') or Jersey ('J') cow. The Jerseys want to create a voting district of 7 contiguous (vertically or horizontally) cow l…

Description It's election time. The farm is partitioned into a 5x5 grid of cow locations, each of which holds either a Holstein ('H') or Jersey ('J') cow. The Jerseys want to create a voting district of 7 contiguous (vertically or horizontally) cow l…

题目描述 农场被划分为5x5的格子,每个格子中都有一头奶牛,并且只有荷斯坦(标记为H)和杰尔西(标记为J)两个品种． 如果一头奶牛在另一头上下左右四个格子中的任一格里,我们说它们相连． 奶牛要大选了．现在有一只杰尔西奶牛们想选择7头相连的奶牛,划成一个竞选区,使得其中它们品种的奶牛比荷斯坦的多．  要求你编写一个程序求出方案总数．  输入 输入5行农场的情况． 输出 输出1行,即划区方案总数． 样例输入 Copy HHHHH JHJHJ HHHHH HJHHJ HHHHH 样例输出 Copy 2…

3392: [Usaco2005 Feb]Part Acquisition 交易 Time Limit: 5 Sec  Memory Limit: 128 MBSubmit: 26  Solved: 18[Submit][Status] Description     奶牛们接到了寻找一种新型挤奶机的任务,为此它们准备依次经过N(1≤N≤50000)颗行星,在行星上进行交易．为了方便,奶牛们已经给可能出现的K(1≤K≤1000)种货物进行了由1到K的标号．由于这些行星都不是十分发达．没有流通的货…

最小最大...又是经典的二分答案做法.. -------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i , n ) for( int i = 0 ; i < n ; ++i ) #def…

1734: [Usaco2005 feb]Aggressive cows 愤怒的牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 217  Solved: 175[Submit][Status][Discuss] Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a st…

1734: [Usaco2005 feb]Aggressive cows 愤怒的牛 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000). His C (2 <= C &l…

[Usaco2005 feb]Aggressive cows 愤怒的牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 407  Solved: 325[Submit][Status][Discuss] Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight…

[Usaco2005 feb]Secret Milking Machine 神秘的挤奶机 题目大意:约翰正在制造一台新型的挤奶机,但他不希望别人知道．他希望尽可能久地隐藏这个秘密．他把挤奶机藏在他的农场里,使它不被发现．在挤奶机制造的过程中,他需要去挤奶机所在的地方T(1≤T≤200)次．他的农场里有秘密的地道,但约翰只在返回的时候用它．农场被划分成N(2≤N≤200)块区域,用1到200标号．这些区域被P(1≤P≤40000)条道路连接,每条路有一个小于10^6的长度L．两块区域之间可能有多条…

Description 约翰正在制造一台新型的挤奶机,但他不希望别人知道．他希望尽可能久地隐藏这个秘密．他把挤奶机藏在他的农场里,使它不被发现．在挤奶机制造的过程中,他需要去挤奶机所在的地方T(1≤T≤200)次．他的农场里有秘密的地道,但约翰只在返回的时候用它．农场被划分成N(2≤N≤200)块区域,用1到200标号．这些区域被P(1≤P≤40000)条道路连接,每条路有一个小于10^6的长度L．两块区域之间可能有多条道路连接．为了减少被发现的可能,约翰不会两次经过农场上的任何一条道路．当然了…

题目链接:BZOJ - 1733 题目分析 直接二分这个最大边的边权,然后用最大流判断是否可以有 T 的流量. 代码 #include <iostream> #include <cstdlib> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; const int MaxN = 200 + 5,…

Description Farmer John is trying to figure out when his last shipment of feed arrived. Starting with an empty grain bin, he ordered and received F1 (1 <= F1 <= 1,000,000) kilograms of feed. Regrettably, he is not certain exactly when the feed arriv…

Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000). His C (2 <= C <= N) cows don't like this barn layout an…

Description     奶牛们接到了寻找一种新型挤奶机的任务,为此它们准备依次经过N(1≤N≤50000)颗行星,在行星上进行交易．为了方便,奶牛们已经给可能出现的K(1≤K≤1000)种货物进行了由1到K的标号．由于这些行星都不是十分发达．没有流通的货币,所以在每个市场里都只能用固定的一种货物去换取另一种货物．    奶牛们带着一种上好的饲料从地球出发,希望进行最少的交易,最终得到所需要的机器．饲料的标号为1,所需要的机器的标号为K.如果任务无法完成,输出-1. Input     第…

http://www.lydsy.com/JudgeOnline/problem.php?id=1676 太水的一题了.. 差分直接搞. #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <algorithm> #include <queue> using namespac…

http://www.lydsy.com/JudgeOnline/problem.php?id=3392 同1674 #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <algorithm> #include <queue> using namespace std; #de…

题目描述 Farmer John is constructing a new milking machine and wishes to keep it secret as long as possible. He has hidden in it deep within his farm and needs to be able to get to the machine without being detected. He must make a total of T (1 <= T <=…

n<=200个点m<=40000条边无向图,求   t次走不经过同条边的路径从1到n的经过的边的最大值   的最小值. 最大值最小--二分,t次不重边路径--边权1的最大流. #include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> //#include<iostream> using namespace std; int n,m,t; #d…

Description Farmer John is trying to figure out when his last shipment of feed arrived. Starting with an empty grain bin, he ordered and received F1 (1 <= F1 <= 1,000,000) kilograms of feed. Regrettably, he is not certain exactly when the feed arriv…

二分答案,贪心判定 #include<iostream> #include<cstdio> #include<algorithm> using namespace std; const int N=100005; int n,m,a[N]; int read() { int r=0,f=1; char p=getchar(); while(p>'9'||p<'0') { if(p=='-') f=-1; p=getchar(); } while(p>=…

水题,20分钟AC,最大值最小,一看就是二分答案... 代码: Description Farmer John has built a <= N <= ,) stalls. The stalls are located along a straight line at positions x1,...,xN ( <= xi <= ,,,). His C ( <= C <= N) cows don't like this barn layout and become ag…

Description Farmer John is constructing a new milking machine and wishes to keep it secret as long as possible. He has hidden in it deep within his farm and needs to be able to get to the machine without being detected. He must make a total of T (1 <…

Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…

大神们都在刷usaco,我也来水一水 1606: [Usaco2008 Dec]Hay For Sale 购买干草   裸背包 1607: [Usaco2008 Dec]Patting Heads 轻拍牛头 神转化,筛法 1609: [Usaco2008 Feb]Eating Together麻烦的聚餐  LIS 1610: [Usaco2008 Feb]Line连线游戏 排序 1611: [Usaco2008 Feb]Meteor Shower流星雨  BFS 1612: [Usaco2008…

杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…

转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…

bzoj上的usaco题目还是很好的(我被虐的很惨. 有必要总结整理一下. 1592: [Usaco2008 Feb]Making the Grade 路面修整 一开始没有想到离散化.然后离散化之后就很好做了.F[I,j]表示第i个点,高度>=j或<=j,f[I,j]=min(f[i-1,j]+abs(b[j]-a[i]),f[I,j-1]) 1593: [Usaco2008 Feb]Hotel 旅馆 线段树 ★1594: [Usaco2008 Jan]猜数游戏 二分答案然后写线段树维护 15…