POJ 2387】的更多相关文章

链式前向星 在做图论题的时候,偶然碰到了一个数据量很大的题目,用vector的邻接表直接超时,上网查了一下发现这道题数据很大,vector可定会超的,不会指针链表的我找到了链式前向星这个好东西,接下来就由一道裸模板题看看链式前向星怎么写,他的优势又在哪里! 题目链接:POJ 2387 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible b…
hdu 2544  求点1到点n的最短路  无向图 Sample Input2 1 //结点数 边数1 2 3 //u v w3 31 2 52 3 53 1 20 0 Sample Output32 堆优化Dijstra模板 # include <iostream> # include <cstdio> # include <cstring> # include <algorithm> # include <cmath> # include &…
POJ 2387 Til the Cows Come Home (图论,最短路径) Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to g…
POJ.2387 Til the Cows Come Home (SPFA) 题意分析 首先给出T和N,T代表边的数量,N代表图中点的数量 图中边是双向边,并不清楚是否有重边,我按有重边写的. 直接跑spfa,dij,floyd都可以. 求1到N的最短路. 代码总览 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #include <stack>…
题目链接:http://poj.org/problem?id=2387 Til the Cows Come Home Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45414   Accepted: 15405 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible…
题目连接: http://poj.org/problem?id=2387 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get ba…
题目链接:http://poj.org/problem?id=2387 题目大意:起点一定是1,终点给出,然后求出1到所给点的最短路径. 注意的是先输入边,在输入的顶点数,不要弄反哦~~~ #include <iostream> #include <cstdio> using namespace std; ][],Min,node[],vis[],t,q; ; void set() { ; i<=; i++) { node[i]=INF; vis[i]=; ; j<=;…
题目链接:http://poj.org/problem?id=2387 题目大意:给你t条边(无向图),n个顶点,让你求点1到点n的最短距离. 解题思路:裸的dijsktra,注意判重边. 代码: #include<cstdio> #include<cmath> #include<cctype> #include<cstring> #include<iostream> #include<algorithm> #include<v…
(POJ)[http://poj.org/problem?id=2387] Til the Cows Come Home Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 69789 Accepted: 23386 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible be…
题目链接:http://poj.org/problem?id=2387 Dijkstra算法: //求某一点(源点)到另一点的最短路,算法其实也和源点到所有点的时间复杂度一样,O(n^2); 图G(V,E),设置一个顶点集合S,不断贪心选择,指导S扩充为V,计算结束. 贪心选择的方法:节点个数n,源节点v,先在S中加入源节点v,初始化源节点,开始扩充S,找到一个点,他离S集合最近,加入到S集合中去,再利用这个点更新S本身中的最短路径. 题目大意:很裸的Dijkstra,但是这里有两点 1.图是双…