Given a binary tree, return the inorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [1,3,2] Follow up: Recursive solution is trivial, could you do it iteratively? 题意: 二叉树中序遍历 Solution1: Recursion code class Soluti…
Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what"{1,#,2,3}"means? > read m…
Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > r…
Level: Medium 题目描述: Given a binary tree, return the inorder traversal of its nodes' values. 思路分析: 实现一棵二叉树的中序遍历,我们可以用简单的递归方法去实现,也可以使用栈去实现,使用第二种方式时,我们沿着根节点先遍历左子树的左孩子,将它们依次压入栈,知道左孩子为空,弹出栈顶节点,这时记录栈顶节点的值,如果栈顶节点的右孩子不为空,压入栈,如果为空,则栈顶元素继续弹出,重复上述操作,就能获得中序遍…
数字对 [题目描述] 小H是个善于思考的学生,现在她又在思考一个有关序列的问题. 她的面前浮现出一个长度为n的序列{ai},她想找出一段区间[L, R](1 <= L <= R <= n). 这个特殊区间满足,存在一个k(L <= k <= R),并且对于任意的i(L <= i <= R),ai都能被ak整除.这样的一个特殊区间 [L, R]价值为R - L. 小H想知道序列中所有特殊区间的最大价值是多少,而有多少个这样的区间呢?这些区间又分别是哪些呢?你能帮助她…
Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. 递归: class Solution { List<Integer> res = new ArrayList<Integer>(); public List<Integer> inord…
Given a binary tree, return the inordertraversal of its nodes' values. For example:Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(in…
package com.example.demo; public class BTree { public int data; public BTree left; public BTree rigth; public boolean hasLeft(){ return left != null; } public boolean hasRigth(){ return rigth != null; } public BTree(){} } class main{ public static vo…
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 给定一个二叉树,返回他的中序遍历的节点的values. 例如: 给定一个二叉树 {1,#,2,3}, 1 \ 2 / 3 返回 [1,3,2]. 笔记: 递归解决方案是微不足道的,你可以用迭代的方法吗? 困惑什么"{1,#,2,3}" 的意思吗? > read more on how binary tree is s…
Given a binary tree, return the postorder traversal of its nodes' values. For example:Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 后序遍历:左孩子->右孩子->根节点 后序遍历最关键的是利用一个指针保存前一个访问过的信…
1064 Complete Binary Search Tree (30 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…
