UVa 483 - Word Scramble

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UVa 483 - Word Scramble

题目大意:给一个由单词组成的句子,只反转单词内部的次序而不改变单词之间的次序.如“I love you.”转换成“I evol .uoy”. #include <cstdio> #include <cstring> int main() { #ifdef LOCAL freopen("in", "r", stdin); #endif int s, e; ]; while (gets(str)) { bool in_word = false;…

UVa 642 - Word Amalgamation

题目:给你一个单词列表.再给你一些新的单词.输出列表中又一次排列能得到此新单词的词. 分析:字符串.对每一个字符串的字母排序生成新的传f(str).总体排序,用二分来查找就可以. 说明:注意输出要满足字典序,先排序后查找. #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> using namespace…

Uva 642 - Word Amalgamation sort qsort

Word Amalgamation In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four wor…

qsort和sort学习与比较

阅读另一篇博文Uva 642 - Word Amalgamation sort qsort 1.qsort函数: 原型: void qsort(void *base, int nelem, int width, int (*fcmp)(const void *,const void *)); 功能: 使用快速排序例程进行排序参数: 1 待排序数组首地址 2 数组中待排序元素数量 3 各元素的占用空间大小 4 指向函数的指针,用于确定排序的顺序说明:qsort函数是ANSI C标准中提…

UVA 1401 - Remember the Word(Trie+DP)

UVA 1401 - Remember the Word [题目链接] 题意:给定一些单词.和一个长串.问这个长串拆分成已有单词,能拆分成几种方式思路:Trie,先把单词建成Trie.然后进行dp.dp[i]表示以i为开头的情况,然后每一个状态仅仅要在Trie树上找到对应的i开头的单词,然后dp[i] = sum{dp[i + len]}进行状态转移就可以代码: #include <cstdio> #include <cstring> const int MOD = 20071…

UVA 1401 Remember the Word

字典树优化DP Remember the Word Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu [Submit] [Go Back] [Status] Description Neal is very curious about combinatorial problems, and now here comes a p…

UVA 1401 Remember the Word（用Trie加速动态规划）

Remember the Word Neal is very curious about combinatorial problems, and now here comes a problem about words. Knowing that Ray has a photographic memory and this may not trouble him, Neal gives it to Jiejie. Since Jiejie can't remember numbers clear…