ZOJ 2334 Monkey King】的更多相关文章

并查集+左偏树.....合并的时候用左偏树,合并结束后吧父结点全部定成树的根节点,保证任意两个猴子都可以通过Find找到最厉害的猴子                       Monkey King Time Limit: 10000MS   Memory Limit: 32768KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description Once in a forest, there lived…
原题链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1389 大致题意:N只相互不认识的猴子(每只猴子有一个战斗力值) 两只不认识的猴子之间发生冲突,两只猴子会分别请出它们认识的最强壮的 猴子进行决斗.决斗之后这,两群猴子都相互认识了. 决斗的那两只猴子战斗力减半...有m组询问 输入a b表示猴子a和b发生了冲突,若a,b属于同一个集合输出-1 否则输出决斗之后这群猴子(已合并)中最强的战斗力值... 具体思路:用并查…
Monkey King Time Limit: 10 Seconds      Memory Limit: 32768 KB Once in a forest, there lived N aggressive monkeys. At the beginning, they each does things in its own way and none of them knows each other. But monkeys can't avoid quarrelling, and it o…
Monkey King Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4714    Accepted Submission(s): 2032 Problem Description Once in a forest, there lived N aggressive monkeys. At the beginning, they e…
ZOJ  1093   Monkey and Banana  (LIS)解题报告 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87125#problem/B 题目: Description 一组研究人员正在设计一项实验,以测试猴子的智商.他们将挂香蕉在建筑物的屋顶,同时,提供一些砖块给这些猴子.如果猴子足够聪明,它应当能够通过合理的放置一些砖块建立一个塔,并爬上去吃他们最喜欢的香蕉.   研究人员有n种类型的砖块,每种类型…
题目地址:P1456 Monkey King 一道挺模板的左偏树题 不会左偏树?看论文打模板,完了之后再回来吧 然后你发现看完论文打完模板之后就可以A掉这道题不用回来了 细节见代码 #include <bits/stdc++.h> using namespace std; const int N = 1e5 + 6; int n, m, f[N], a[N], l[N], r[N], d[N]; //类并查集路径压缩 int get(int x) { if (x == f[x]) return…
HDU 1069 Monkey and Banana / ZOJ 1093 Monkey and Banana (最长路径) Description A group of researchers are designing an experiment to test the IQ of a monkey. They will hang a banana at the roof of a building, and at the mean time, provide the monkey with…
As everyone known, The Monkey King is Son Goku. He and his offspring live in Mountain of Flowers and Fruits. One day, his sons get n peaches. And there are m monkeys (including GoKu), they are numbered from 1 to m, GoKu’s number is 1. GoKu wants to d…
我们知道如果要我们给一个序列排序,按照某种大小顺序关系,我们很容易想到优先队列,的确很方便,但是优先队列也有解决不了的问题,当题目要求你把两个优先队列合并的时候,这就实现不了了 优先队列只有插入 删除 取数的操作,但是却没有合并两个优先队列的操作. 这也是它的局限所在. 本次要介绍的左偏树拥有优先队列的所有功能,同时它还可以合并操作.  树的复杂度都比较低,一般log(n)就够了,左偏树也是如此,左偏树如果一个个结点暴力插入复杂度最大为nlog(n) 还有一种仿照二叉树的算法,这里不做介绍. …
Monkey King Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6667    Accepted Submission(s): 2858 Problem Description Once in a forest, there lived N aggressive monkeys. At the beginning, they e…