You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

An intuitive DP - should be 'medium'. class Solution { public: int maxEnvelopes(vector<pair<int, int>>& envelopes) { int n = envelopes.size(); ; ) ; // Sort by Area sort(envelopes.begin(), envelopes.end(), [](const pair<int, int> &am…

https://leetcode.com/problems/russian-doll-envelopes/ You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater tha…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

题目描述: You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. Wh…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope.What is t…

这个题大意很好理解,通过例子就能明白,很像俄罗斯套娃,大的娃娃套小的娃娃.这个题是大信封套小信封,每个信封都有长和宽,如果A信封的长和宽都要比B信封的要大,那么A信封可以套B信封,现在给定一组信封的大小,要求输出最多有几个信封能套在一起. Example:Given envelopes = [[5,4],[6,4],[6,7],[2,3]], the maximum number of envelopes you can Russian doll is 3 ([2,3] => [5,4] =>…

You have a number of envelopes with widths and heights given as a pair of integers (w, h). One envelope can fit into another if and only if both the width and height of one envelope is greater than the width and height of the other envelope. What is…

Leetcode354 暴力的方法是显而易见的 O(n^2)构造一个DAG找最长链即可. 也有办法优化到O(nlogn) 注意 信封的方向是不能转换的. 对第一维从小到大排序,第一维相同第二维从大到小排序. 维护一个符合题意的队列,当队列中的第二维均比当前信封的第二维小时,必然可以增加到队尾. 如果不然,可以让当前信封作为“替补”,它可以在恰当的时候代替恰好比它大的信封. 当替补们足够替换所有已有信封时,就可以增加新的信封了. 比较抽象,不过这个技巧很有趣. 看代码吧,很清晰. class So…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than…

尽量抽空刷LeetCode,持续更新 刷题记录在github上面,https://github.com/Zering/LeetCode 2016-09-05 300. Longest Increasing Subsequence 问题:https://leetcode.com/problems/longest-increasing-subsequence/ 分析:http://zering.me/2016/09/02/Longest-Increasing-Subsequence/ 源码:http…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

二分查找法作为一种常见的查找方法,将原本是线性时间提升到了对数时间范围,大大缩短了搜索时间,具有很大的应用场景,而在LeetCode中,要运用二分搜索法来解的题目也有很多,但是实际上二分查找法的查找目标有很多种,而且在细节写法也有一些变化.之前有网友留言希望博主能针对二分查找法的具体写法做个总结,博主由于之前一直很忙,一直拖着没写,为了树立博主言出必行的正面形象,不能再无限制的拖下去了,那么今天就来做个了断吧,总结写起来~ (以下内容均为博主自己的总结,并不权威,权当参考,欢迎各位大神们留言讨论…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

Binary Search基础 应用于已排序的数据查找其中特定值,是折半查找最常的应用场景.相比线性查找(Linear Search),其时间复杂度减少到O(lgn).算法基本框架如下: //704. Binary Search int search(vector<int>& nums, int target) { //nums为已排序数组 ,j=nums.size()-; while(i<=j){ ; if(nums[mid]==target) return mid; ; ;…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

Given an unsorted array of integers, find the length of longest increasing subsequence. Example: Input: [10,9,2,5,3,7,101,18] Output: 4 Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4. Note: There may be more…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

Hello everyone, I am a Chinese noob programmer. I have practiced questions on leetcode.com for 2 years. During this time, I studied a lot from many Great Gods' articles. After worship, I always wanted to write an article as they did, and now I take t…

删除不常考,面试低频出现题目 删除重复代码题目(例:链表反转206题,代码在234题出现过) 删除过于简单题目(例:100题:Same Tree) 删除题意不同,代码基本相同题目(例:136 & 389,保留一个) 适用人群:有一定刷题基础,算法基础,二刷人群. 建议:400题全部刷完,再精刷这250题. ID Title 1 Two Sum 3 Longest Substring Without Repeating Characters 4 Median of Two Sorted Array…

1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…

# Title Solution Acceptance Difficulty Frequency     4 Median of Two Sorted Arrays       27.2% Hard     10 Regular Expression Matching       25.6% Hard     23 Merge k Sorted Lists       35.8% Hard     25 Reverse Nodes in k-Group       37.7% Hard    …

[4]Median of Two Sorted Arrays [29]Divide Two Integers [33]Search in Rotated Sorted Array [34]Find First and Last Position of Element in Sorted Array [35]Search Insert Position [50]Pow(x, n) [69]Sqrt(x) [74]Search a 2D Matrix (2019年1月25日,谷歌tag复习)剑指of…