Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 这一题可以用排序之后查看序列正中间那个元素的方法来解.但…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 hashmap统计次数 摩尔投票法 Moore Voting 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element-ii/description/ 题目描述 Given an integer array of size n, find all elements that ap…

Majority Element II Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint…

Majority Element II Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Ou…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it possibly have? Do you have a better hint? Suggest it! [题目分析]…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路: 找到一个数组中出现次数超过一半的数.排序.哈希等…

169. Majority Element 求超过数组个数一半的数 可以使用hash解决,时间复杂度为O(n),但空间复杂度也为O(n) class Solution { public: int majorityElement(vector<int>& nums) { unordered_map<int,int> count; int n=nums.size(); ;i<n;i++){ ) return nums[i]; } ; } }; 使用投票法,时间复杂度为O(…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Note: The algorithm should run in linear time and in O(1) space. Example 1: Input: [3,2,3] Output: [3] Example 2: Input: [1,1,1,3,3,2,2,2] Output: [1,2] 169. Maj…

Total Accepted: 23103 Total Submissions: 91679 Difficulty: Medium Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements cou…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. class Solution { public: //O(n) Space compexity vector<int> majorityElement01(vector<int>&…

题目 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits: Special thanks t…

题目:Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. int majorityElement(vecto…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 求大于数组一半的元素,思想主要是对于大于数组一般的元素,…

一. 题目描写叙述 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 二. 题目分析 题目说到,给定一个数…

Description Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input…

这题用到的基本算法是Boyer–Moore majority vote algorithm wiki里有示例代码 1 import java.util.*; 2 public class MajorityVote { 3 public int majorityElement(int[] num) { 4 int n = num.length; 5 int candidate = num[0], counter = 0; 6 for (int i : num) { 7 if (counter ==…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 题目标签:Array 题目给了我们一个 nums array, 让我们找出所有 数量超过 n/3 的众数.这一题与 众数之一 的区别在于,众数之一 只要找到一个 众数大于 n/2 的就可以.这一题要找到所…

就是简单的应用多数投票算法(Boyer–Moore majority vote algorithm),参见这道题的题解. class Solution { public: vector<int> majorityElement(vector<int>& nums) { ,cnt2=,ans1=,ans2=; for(auto n:nums){ if(n==ans1){ cnt1++; } else if(n==ans2){ cnt2++; } ){ ans1=n; cnt1…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 解题思路: <编程之美>寻找发帖水王的原题,两次遍历,一次遍历查找可能出现次数超过nums.length/3的数字,(出现三次不同的数即抛弃),第二次验证即可. JAVA实现如下: public Lis…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 解法:参考编程之美129页,寻找发帖水王 代码如下: public class Solution { public List<Integer> majorityElement(int[] nums) {…

网址:https://leetcode.com/problems/majority-element-ii/ 参考:https://blog.csdn.net/u014248127/article/details/79230221 摩尔投票算法( Boyer-Moore Voting Algorithm) class Solution { public: vector<int> majorityElement(vector<int>& nums) { vector<in…

给定一个大小为 n 的数组,找出其中所有出现超过 ⌊ n/3 ⌋ 次的元素. 你的算法应该在O(1)空间中以线性时间运行. 详见:https://leetcode.com/problems/majority-element-ii/description/ 摩尔投票法 Moore Voting Java实现: class Solution { public List<Integer> majorityElement(int[] nums) { List<Integer> res=ne…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 代码如下:(方法一:超内存) public class Solution { public List<Integer> majorityElement(int[] nums) { List<Int…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 求主元素,这次的是大于sz/3就算是主元素,可以分为两轮查找,第一轮先查找元素数目较多的两个元素(可能不属于主元素),第二次再遍历来查找上面两个元素是否符合条件,代码如下: class Solution…

这是悦乐书的第181次更新,第183篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第40题(顺位题号是169).给定大小为n的数组,找到数组中出现次数超过n/2的元素.假设该数组非空,并且该元素始终存在于数组中.例如: 输入:[3,2,3] 输出:3 输入:[2,2,1,1,1,2,2] 输出:2 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测试. 02 第一种解法 我们可以先将数组排序,然后使…

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 思路: [LeetCode 169]Majority Element 的拓展,这回要求的是出现次数超过三分之一次的数字咯,动动我们的大脑思考下,这样的数最多会存在几个呢,当然是2个嘛.因此,接着上一题的方…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input: [3,2,3] Ou…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 思路 hashmap统计次数 摩尔投票法 Moore Voting 位运算统计位数 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/majority-element/ Total Accepted: 110538 Total Submissions: 268289 Difficulty: Easy 题目…

［抄题］: Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. [暴力解法]: 时间分析: 空间分析: ［奇…

169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…