Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…

原题链接在这里:https://leetcode.com/problems/find-all-anagrams-in-a-string/ 题目: Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s a…

[leetcode]438. Find All Anagrams in a String Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than…

Question 438. Find All Anagrams in a String Solution 题目大意:给两个字符串,s和p,求p在s中出现的位置,p串中的字符无序,ab=ba 思路:起初想的是求p的全排列,保存到set中,遍历s,如果在set中出现,s中的第一个字符位置保存到结果中,最后返回结果.这种思路执行超时.可能是求全排列超时的. 思路2:先把p中的字符及字符出现的次数统计出来保存到map中,再遍历s,这个思路和169. Majority Element - LeetCode…

problem 438. Find All Anagrams in a String solution1: class Solution { public: vector<int> findAnagrams(string s, string p) { if(s.empty()) return {}; vector<, ); for(auto a:p) pv[a]++; int sn = s.size(); ; while(i<sn) { vector<int> tmp…

https://leetcode.com/problems/anagrams/ Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat&q…

题目链接: https://leetcode.com/problems/anagrams/?tab=Description   Problem:给一个字符串数组,将其中的每个字符串进行分组,要求每个分组中的各个字符串所包含的字母都相同对字母的前后顺序没有要求!       使用 Map<String, List<String>> map 进行求解   给定的字符串数组为 String[] strs 1.当strs为空时返回new ArrayList<List<Strin…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 49: Anagramshttps://leetcode.com/problems/anagrams/ Given an array of strings, return all groups of strings that are anagrams.Note: All inputs will be in lower-case. === Comments by Dabay==…

原题: 438. Find All Anagrams in a String 解题: 两个步骤 1)就是从s中逐步截取p长度的字符串 2)将截取出的字符串和p进行比较,比较可以用排序,或者字典比较(这两种方法提交后都超时了) 代码如下(提交超时): class Solution { public: vector<int> findAnagrams(string s, string p) { int lenp = p.length(); int lens = s.length(); int i=…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…