E - Level K Palindrome】的更多相关文章

题目大意: As a token of his gratitude, Takahashi has decided to give Snuke a level-KK palindrome. A level-LL palindrome, where LL is a non-negative integer, is defined as follows: Let rev(s)rev(s) denote the reversal of a string ss. A string ss is said t…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 统计奇数字符出现次数 日期 题目地址:https://leetcode-cn.com/problems/construct-k-palindrome-strings/ 题目描述 给你一个字符串 s 和一个整数 k .请你用 s 字符串中 所有字符 构造 k 个非空 回文串 . 如果你可以用 s 中所有字符构造 k 个回文字符串,那么请你返回 True…
题目如下:Given a sequence of binary trees, you are to write a program that prints a level-order traversal of each tree. In this problem each node of a binary tree contains a positive integer and all binary trees have have fewer than 256 nodes. In a level…
题目描述:输入一个单向链表,输出该链表中倒数第k个节点,链表的倒数第0个节点为链表的尾指针. 最普遍的方法是,先统计单链表中结点的个数,然后再找到第(n-k)个结点.注意链表为空,k为0,k为1,k大于链表中节点个数时的情况 .时间复杂度为O(n).代码略. 这里主要讲一下另一个思路,这种思路在其他题目中也会有应用.主要思路就是使用两个指针,先让前面的指针走到正向第k个结点 ,这样前后两个指针的距离差是k-1,之后前后两个指针一起向前走,前面的指针走到最后一个结点时,后面指针所指结点就是倒数第k…
 Trees on the level  Background Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinking Machines' CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms i…
描述 Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinking Machines' CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms in computer graphics. This pro…
思想:採用基于层序遍历的方法. 用level扫描各层节点,若某一层的节点出队后.rear指向该层中最右节点.则将rear赋值给last(对于第一层.last=1).在出队时,若front=last,表示这一层处理完成,让层号level增1,并置last为下一层最右节点.那么怎样求一层的最右节点呢?这是由于第一层仅仅有一个节点,它就是最右节点.对于其它层.上一层最右节点最后进队的孩子一定是该层的最右节点. 比如,对于如图所看到的的二叉树.求k=3的叶子节点个数的步骤例如以下:level=1;A进队…
Trees on the level Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status Description   Background Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinki…
Trees on the level Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 584    Accepted Submission(s): 195题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1622 Problem Description Trees are fundamental…
题目链接:https://vjudge.net/contest/209862#problem/B 题目大意: Trees on the level Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 591    Accepted Submission(s): 200 Problem Description Trees are fundame…
内存池技术就是创建一个内存池,内存池中保存着可以使用的内存,可以使用数组的形式实现,然后创建一个空闲列表,开始时将内存池中所有内存放入空闲列表中,表示空闲列表中所有内存都可以使用,当不需要某一内存时,将其放入空闲列表中,使内存可以循环使用.空闲列表可以用不定长数组vector定义,内存池和空闲列表的类型由使用内存的数据决定,如果使用内存的数据是用户自定义的结构体类型,则使用此类型.由于大部分情况下是使用指针进行内存调用,所以空闲列表中存储的是相应的指针. 具体实例如下: 题目: Trees ar…
Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinking Machines’ CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms in computer graphics. This proble…
  跳表(SkipList)是一种随机化的数据结构,目前在redis和leveldb中都有用到它,它的效率和红黑树以及 AVL 树不相上下,但跳表的原理相当简单,只要你能熟练操作链表, 就能轻松实现一个 SkipList. 考虑一个有序表: 从该有序表中搜索元素 < 23, 43, 59 >,需要比较的次数分别为 < 2, 4, 6 >,总共比较的次数为 2 + 4 + 6 = 12 次. 有没有优化的算法吗?链表是有序的,但不能使用二分查找.类似二叉搜索树,我们把一些节点提取出来…
题目: 给定以下二叉树: struct node { node *left, *right; int value; }; 要求编写函数 node* foo(node *node, unsigned int m, unsigned int k); 输出以 node 为根的二叉树第 m 层的第 k 个节点值.(level, k 均从 0 开始计数) 注意:此树不是完全二叉树: 所谓的第K个节点,是本层中从左到右的第K个节点 思路: 广度优先遍历,即层次遍历,通过队列来实现. 代码: struct n…
size_t _FindLeafSize(Node* root)     //求二叉树叶子节点的个数    {        //static size_t count = 0;        if (root == NULL)            return 0; if (root->_left == NULL&&root->_right == NULL);        return 1; return _FindLeafSize(root->_right) +…
Trees are fundamental in many branches of computer science (Pun definitely intended). Current state- of-the art parallel computers such are based on fat trees . Quad- and octal-trees are fundamental to many algorithms in computer graphics. This probl…
1. 节点个数 function getNodeNum(root){ if(root == null){ return 0; } //+1为root的计数 return getNodeNum(root.left) + getNodeNum(root.right) + 1; } 2. 叶子个数 function getLeafNum(root){ if(root == null){ return 0; } if(root.left == null && root.right == null)…
紫书:P150 uva122 Background Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinking Machines' CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms in comp…
Background Trees are fundamental in many branches of computer science. Current state-of-the art parallel computers such as Thinking Machines' CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms in computer graphics.…
Trees are fundamental in many branches of computer science (Pun definitely intended). Current stateof-the art parallel computers such as Thinking Machines' CM-5 are based on fat trees. Quad- and octal-trees are fundamental to many algorithms in compu…
很久没有写文章了,主要是最近一段时间没有以前那么多空暇空间,内存和CPU占用率一致都很高,应前几日群里网友的要求,今天发个表面模糊的小程序来找回之前写博客的热情吧. 国内我认为,破解表面模糊的原理的最早作者是我一直很崇拜的一位女士,她不会编程,英文也不怎么好,仅凭计算器和Excel两个工具破解了PS了很多  算法,真是个巾帼英雄. 详见地址:http://www.missyuan.com/thread-428384-1-1.htm 网上的有关该算法的matlab实现参考:http://www.c…
1.cache是什么 cache这个名字用来称呼两种物理世界中存在的概念,硬体cache和cache机制.下面来分别介绍. 硬体cache:硬体cache是一种用肉眼可以看得见用皮肤可以摸得着的物品,它是由SRAM(static random-access memory)构成(在计算机硬件系统中main memory由DRAM(dynamic random-access memory)构成.硬体cache在CPU中,直接与寄存器进行数据的传输. cache机制:有两块存储区域,区域A,区域B,区…
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 178    Accepted Submission(s): 93 Problem Description ztr love reserach substring.Today ,he has n string.Now ztr want to konw,can he take out exac…
struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: ListNode* rotateRight(ListNode* head, int k) { int level = -1; int size = 0; ListNode *ptr = head; while(ptr != nullptr) //一定要找到size,并取余,不然…
[.net 面向对象编程基础] (20)  LINQ使用 通过上节LINQ的基础知识的学习,我们可以开始使用LINQ来进行内存数据的查询了,我们上节说了LINQ的定义为:Language Integrated Query(语言集成查询)的简称,它是集成在.NET编程语言中的一种特性. 1.LINQ的构架 从这幅图中,我们可以知道LINQ包括五个部分:LINQ to Objects.LINQ to XML.LINQ to SQL.LINQ to DataSet.LINQ to Entities.…
概要 本章对Java.util.concurrent包中的ConcurrentSkipListMap类进行详细的介绍.内容包括:ConcurrentSkipListMap介绍ConcurrentSkipListMap原理和数据结构ConcurrentSkipListMap函数列表ConcurrentSkipListMap源码分析(JDK1.7.0_40版本)ConcurrentSkipListMap示例 转载请注明出处:http://www.cnblogs.com/skywang12345/p/…
概述 Log4net 有三个主要组件:loggers,appenders 和 layouts.这三个组件一起工作使得开发者能够根据信息类型和等级(Level)记录信息,以及在运行时控制信息的格式化和信息的写入位置(如控制台,文件,内存,数据库等).过滤器(filter)帮助这些组件,控制追加器(appender)的行为和把对象转换成字符串的对象渲染. 如果对log4net的基本使用并不是很清楚,可以参考我的另一遍介绍:Log4net入门使用 日志(Loggers) 日志请求是通过调用一个日志实例…
A. Plus and Square Root time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder is playing a game. There is a number displayed on the screen and there are two buttons, ' + ' (plus) an…
<%--总的弹出层--%> <div class="tcck" id="joinclub" style="display:none"> <table style="width:430px; height:7px;" border="0" cellpadding="0" cellspacing="0" > <tr style=&…
Deep Generative Image Models using a Laplacian Pyramid of Adversarial Networks NIPS 2015  摘要:本文提出一种 generative parametric model 能够产生高质量自然图像.我们的方法利用 Laplacian pyramid framework 的框架,从粗到细的方式,利用 CNN 的级联来产生图像.在金字塔的每一层,都用一个 GAN,我们的方法可以产生更高分辨率的图像.    引言:在计算…