[题目描述] Implement an assignment operator overloading method. Make sure that: The new data can be copied correctly The old data can be deleted / free correctly. We can assign like  A = B = C 实现赋值运算符重载函数,确保: 新的数据可准确地被复制 旧的数据可准确地删除/释放 可进行A = B = C赋值 [题目链…

拷贝构造函数(copy constructor)被用来以一个对象来初始化同类型的另一个对象,拷贝赋值运算符(copy assignment operator)被用来将一个对象中的值拷贝到同类型的另一个对象中: class Widget { public: Widget(); // default constructor Widget(const Widget& rhs); // copy constructor Widget& operator=(const Widget& rhs…

拷贝构造函数(copy constructor)被用来以一个对象来初始化同类型的另一个对象,拷贝赋值运算符(copy assignment operator)被用来将一个对象中的值拷贝到同类型的另一个对象中: class Widget { public: Widget(); // default constructor Widget(const Widget& rhs); // copy constructor Widget& operator=(const Widget& rhs…

We have discussed assignment operator overloading for dynamically allocated resources here . This is a an extension of the previous post. In the previous post, we discussed that when we don't write our own assignment operator, compiler created assign…

The answer is same as Copy Constructor. If a class doesn't contain pointers, then there is no need to write assignment operator and copy constructor. The compiler creates a default copy constructor and assignment operators for every class. The compil…

Difficulty Level: Rookie Consider the following C++ program. 1 #include<iostream> 2 #include<stdio.h> 3 4 using namespace std; 5 6 class Test 7 { 8 public: 9 Test() 10 { 11 } 12 Test(const Test &t) 13 { 14 cout<<"Copy constructo…

看了android下的代码,好长时间没看了,有个关于C++的知识点不是很清楚,查了下: 如何使用基类中的赋值运算符? 引述自http://stackoverflow.com/questions/1226634/how-to-use-base-classs-constructors-and-assignment-operator-in-c 参考:<C++ Primer>4ed_CN  p_495 编译器的默认设置: struct base { base() { std::cout <<…

eg: num = 10 num += 1 # 等价于 num = num + 1 => 11 print(num) 特殊操作: 1.链式赋值 a = b = num print(a, b, num, id(a), id(b), id(num)) 2.交叉赋值 # 传统交换赋值x = 10 y = 20 temp = xx = yy = tempprint(x, y) Output:20 10 x, y = y, x print(x, y) 3.解压赋值 ls = [3, 1, 2] a, b,…

说明:文章中关于operator=实现的示例,从语法上是对的,但逻辑和习惯上都是错误的. 参见另一篇专门探究operator=的文章:<c++,operator=>http://www.cnblogs.com/mylinux/p/4113266.html 1.构造函数与析构函数不会被继承:[1] 不是所有的函数都能自动地从基类继承到派生类中的.构造函数和析构函数是用来处理对象的创建和析构的,它们只知道对在它们的特殊层次的对象做什么.所以,在整个层次中的所有的构造函数和析构函数都必须被调用,也就…

C++ operator overload -- 操作符重载 2011-12-13 14:18:29 分类: C/C++ 操作符重载有两种方式,一是以成员函数方式重载,另一种是全局函数. 先看例子 #include <iostream> #include <string> using namespace std; /* defualt operator= differ from my own one. * assign 0 or 1 to TEST_EQ, look the dif…