Holiday's Accommodation Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 200000/200000 K (Java/Others)Total Submission(s): 2009    Accepted Submission(s): 558 Problem Description Nowadays, people have many ways to save money on accommodation w…

Holiday's Accommodation Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 200000/200000 K (Java/Others)Total Submission(s): 2925    Accepted Submission(s): 894 Problem Description Nowadays, people have many ways to save money on accommodation w…

题意:给n个点,每个点有一个人,有n-1条有权值的边,求所有人不在原来位置所移动的距离的和最大值. 析:对于每边条,我们可以这么考虑,它的左右两边的点数最少的就是要加的数目,因为最好的情况就是左边到右边,右边到左边,然后用dfs就可以解决了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <…

Problem Description Nowadays, people have many ways to save money on accommodation when they are on vacation. One of these ways is exchanging houses with other people. Here is a group of N people who want to travel around the world. They live in diff…

题目链接:  HDU 4118 Holiday's Accommodation 分析: 可以知道每条边要走的次数刚好的是这条边两端的点数的最小值的两倍. 代码: #include<iostream> #include<cstdio> #include<cstring> #include<stack> using namespace std; const int maxn=100000+10; struct node{ int to, dix, next; }…

题目链接: Holiday's Accommodation Time Limit: 8000/4000 MS (Java/Others)     Memory Limit: 200000/200000 K (Java/Others) Problem Description   Nowadays, people have many ways to save money on accommodation when they are on vacation.One of these ways is e…

题意:给n个点,每个点有一个人,有n-1条有权值的边,求所有人不在原来位置所移动的距离的和最大值.不能重复 这题的方法很有看点啊,标记为巩固题 Sample Input 1 4 1 2 3 2 3 2 4 3 2   Sample Output Case #1: 18 //1去4,4去1,2去3,3去2   对于每条边,因为大家都想走的最远,那么相当于让边两端的人交换,花费就是 边长*经过边的人数 ans = Σ (每条路长 l )*(经过这条路的最大次数 f ) f = 2 * 这条边左边节点…

题意:有n间房子,之间有n-1条道路连接,每个房间里住着一个人,这n个人都想到其他房间居住,并且每个房间不能有两个人,问所有人的路径之和最大是多少? 分析:对于每条边来说,经过改边的人由该边两端元素个数较小者决定 #pragma comment(linker, "/STACK:1024000000,1024000000") #include"stdio.h" #include"string.h" #include"queue"…

思路:其实就是让每一条路有尽量多的人走. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<map> #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cst…

比赛链接: http://acm.hust.edu.cn/vjudge/contest/view.action?cid=44903#overview 题目来源: 2011 Asia ChengDu Regional Contest Wine93有话说: 爆0, oh-year!   ID Origin Title   13 / 118 Problem A HDU 4111 Alice and Bob 137 / 358 Problem B HDU 4112 Break the Chocolate…