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题目链接:Cards 听说这道题是染色问题的入门题,于是就去学了一下\(Bunside\)引理和\(P\acute{o}lya\)定理(其实还是没有懂),回来写这道题. 由于题目中保证"任意多次洗牌都可用这\(m\)种洗牌法中的一种代替",于是有了封闭性. 结合律显然成立. 题目中还保证了"对每种洗牌法,都存在一种洗牌法使得能回到原状态",逆元也有了. 只剩下一个单位元,我们手动补上.单位元就是不洗牌. 所以所有的洗牌方案构成了一个置换群.于是就可以用$Bunsid…
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1004: [HNOI2008]Cards Description 小春现在很清闲,面对书桌上的N张牌,他决定给每张染色,目前小春只有3种颜色:红色,蓝色,绿色.他询问Sun有 多少种染色方案,Sun很快就给出了答案.进一步,小春要求染出Sr张红色,Sb张蓝色,Sg张绝色.他又询问有多少种方 案,Sun想了一下,又给出了正确答案. 最后小春发明了M种不同的洗牌法,这里他又问Sun有多少种不同的染色方案. 两种染色方法相同当且仅当其中一种可以通过任意的洗牌法(即可以使用多种洗牌法,而每种方法可以使…
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转载请注明 http://blog.csdn.net/eclipsexys 翻译自Developer Android.时间仓促,有翻译问题请留言指出,谢谢 创建Lisst和Cards 在你的应用程序创建复杂的清单,并与材料设计风格卡.您能够使用RecyclerView和CardView部件. 创建RecyclerView 该RecyclerView widget是ListView中的更先进,更灵活的版本号.这个小工具是一个容器.用于显示.能很有效地维护了意见数量有限,滚动大的数据集. 当你有收集…
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Define “Straight” as 5 cards with consecutive numbers. Determine if the deck can be fully divided into sets of “Straight”. Example: 1, 2, 3, 4, 4, 5, 5, 6, 7, 8 -> TrueYou may assume the cards are sorted 这个是用一个hashtable,key是数字,value是出现次数 然后遍历原数组,每一个数…
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Cards 题意: 给你n个牌,n是偶数,要你把这些牌分给n/2个人,并且让每个人的牌加起来相等. 题解: 这题我做的时候,最先想到的是模拟,之后码了一会,发现有些麻烦,就想别的方法.之后发现只要把它给的数排序就好了,排完序后输出原来的位置就好,因为每2个都能配对所以最小肯定配最大,第二小配第二大-- 之后就可以a了 代码: #include <bits/stdc++.h> using namespace std; const int INF=0x3f3f3f3f; typedef long…
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直接用STL里的queue模拟即可. #include <cstdio> #include <queue> using namespace std; ; int discarded[maxn], cnt; int main() { int n; && n) { cnt = ; queue<int> Q; ; i <= n; i++) Q.push(i); ) { discarded[cnt++] = Q.front(); Q.pop(); int…