You are given an integer array A.  From some starting index, you can make a series of jumps.  The (1st, 3rd, 5th, ...) jumps in the series are called odd numbered jumps, and the (2nd, 4th, 6th, ...) jumps in the series are called even numbered jumps.…

You are given an integer array A.  From some starting index, you can make a series of jumps.  The (1st, 3rd, 5th, ...) jumps in the series are called odd numbered jumps, and the (2nd, 4th, 6th, ...) jumps in the series are called even numbered jumps.…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetcode.com/problems/odd-even-jump/ 题目描述 You are given an integer array A. From some starting index, you can make a series of jumps. The (1st, 3rd, 5th, -…

分析 注意到跳跃的方向是一致的,所以我们需要维护一个数接下来跳到哪里去的问题.换句话说,就是对于一个数\(A_i\),比它大的最小值\(A_j\)是谁?或者反过来. 这里有两种方案,一种是单调栈,简单说一下思路:维护一个递减的单调栈,每次放入元素时将比它大的栈顶元素弹出(说明这些元素都能在递减的情况下都能跳到它),直到没有元素或者没有符合条件的元素位置.反过来依然,然后扫一遍就可以了. 这里采用Java的TreeMap解决问题(也就是c++的map).我们倒过来遍历一遍这个数组,那么只要Tree…

You are given an integer array A.  From some starting index, you can make a series of jumps.  The (1st, 3rd, 5th, ...) jumps in the series are called odd numbered jumps, and the (2nd, 4th, 6th, ...) jumps in the series are called even numbered jumps.…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

# Title Solution Acceptance Difficulty Frequency     4 Median of Two Sorted Arrays       27.2% Hard     10 Regular Expression Matching       25.6% Hard     23 Merge k Sorted Lists       35.8% Hard     25 Reverse Nodes in k-Group       37.7% Hard    …

Contest 111 (题号941-944)(2019年1月19日,补充题解,主要是943题) 链接:https://leetcode.com/contest/weekly-contest-111 [941]Valid Mountain Array(第一题 3分)(google tag) 判断一个数组是不是 Mountain 数组. Mountain 数组的定义是 A.length >= 3There exists some i with 0 < i < A.length - 1 su…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

[ONTAK2010] Peaks 加强版 题目大意:原题变为强制在线查询 Solution 读入山高,排序后依然建立树链,初始化并查集,初始化重构树新节点标号为\(n+1\) 读入边,按照边权从小到大排序 \(kruskal\)重构树 如果是在同一并查集里,\(continue\) 如果不在,建立新节点,两个节点的\(a\)都是新节点,并且记录在重构树上的\(fa\),合并树链 倍增处理重构树 读入询问,如果上一次询问的答案不为\(-1\),\(xor\)上一次的答案,在重构树上跳,查询答案…

算术和逻辑指令 ADC : 带进位的加法 (Addition with Carry) ADC{条件}{S} <dest>, <op 1>, <op 2> dest = op_1 + op_2 + carry ADC 将把两个操作数加起来,并把结果放置到目的寄存器中.它使用一个进位标志位,这样就可以做比 32 位大的加法.下列例子将加两个 128 位的数. 128 位结果: 寄存器 0.1.2.和 3 第一个 128 位数: 寄存器 4.5.6.和 7 第二个 128 位…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. Example 1: Input…

Complete The Pattern #6 - Odd Ladder Task: You have to write a function pattern which creates the following pattern (see examples) up to the desired number of rows. If the Argument is 0 or a Negative Integer then it should return "" i.e. empty s…

跳跃游戏 1 ［抄题］: ［思维问题］: ［一句话思路］: ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 由于要用iteration, 不能return, 每次都要对can数组进行操作 循环函数中不用return false, 因为最终能不能是can数组决定的 ［二刷］: ［三刷］: ［四刷］: ［五刷］: [五分钟肉眼debug的结果]: ［总结］: ［复杂度］:Time complexity: O() Space c…

\(JUMP\) 很容易写出转移柿子 \[f_i=\min_{p_j<p_i}\{(h_i-h_j)^2+f_j\}+w_i\] 把\(\min\)里面的东西展开一下 \[f_j=\min_{p_j<p_i}\{-2h_jh_i+h_j^2+f_j\}+h_i^2+w_i\] 里面的\(\min\)是一个一次函数 首先这是一个类似于区间查询的东西,我们可以用树状数组 里面查询的东西是一个最小值,也就是说我们要资瓷插入一次函数并求最小值,超哥线段树就行了 所以这其实是个树套树,不过树状数组套什么…

laviewpbt  2014.8.4 编辑 Email:laviewpbt@sina.com   QQ:33184777 最近闲来蛋痛,看了一些显著性检测的文章,只是简单的看看,并没有深入的研究,以下将研究的一些收获和经验共享. 先从最简单的最容易实现的算法说起吧: 1. LC算法 参考论文:Visual Attention Detection in Video Sequences Using Spatiotemporal Cues. Yun Zhai and Mubarak Shah.  P…

A frog is crossing a river. The river is divided into x units and at each unit there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water. Given a list of stones' positions (in units) in sorted ascending ord…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. For example:A = …

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

我一开始认为这是一道DP的题目.其实,可以维护一个maxReach,并对每个元素更新这个maxReach = max(maxReach, i + nums[i]).注意如果 i>maxReach,说明从起点开始能跳到的最远距离不到i, 所以i后面的点也就无法到达了.另外如果 maxReach >= n-1 说明已经可以跳到终点了,之后的点也就不用继续检查了. class Solution(object): def canJump(self, nums): """…

错误“LC.exe”已退出,代码为 -1. 可能的原因是: 这个第三方组件是个商业组件,他在组件的主使用类定义了 LicenseProvider(typeof(LicFileLicenseProvider)) 这个Attribute. VS在编译时检测到这个类的时候,会检查到组件使用的是LicFileLicenseProvider这个属性,表示有组件使用的是把许可的辅助信息保存在license.licx文件中,这个文件保存在vs2005中解决方案资源管理器中的Properties文件夹内. 这个…

题目: Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of j…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. For example:A = …

gdb或者vlagrind报告: ==14569== Jump to the invalid address stated on the next line ==14569== at 0x0: ??? ==14569== Address 0x0 is not stack'd, malloc'd or (recently) free'd 错误原因:函数通过jmp,call,ret等指令跳转到0x00,错误可能出现的范围 1.函数缓冲区溢出覆盖了返回地址,然后又调用了return,例如 #inclu…

今天使用VS2015开发一个Winform程序,手一抖拖错了一个第三方控件,然后将其去掉并删除相关的引用,结果导致了LC.exe错误:"Lc.exe已退出,代码为-1 ". 经过上网搜索,找到如下解决方案: 1.把项目文件夹下Properties文件夹下的licenses.licx文件删除,重新编译即可: 2.文本方式打开*.csproj文件,在文件中查找licenses.licx字样,删除对应节点. 目前已经成功解决该问题.…