Count the Buildings

【Count the Buildings】的更多相关文章

【HDU 4372】 Count the Buildings (第一类斯特林数)

Count the Buildings Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1249 Accepted Submission(s): 408 Problem Description There are N buildings standing in a straight line in the City, numbere…

[Hdu4372] Count the Buildings

[Hdu4372] Count the Buildings Description There are N buildings standing in a straight line in the City, numbered from 1 to N. The heights of all the buildings are distinct and between 1 and N. You can see F buildings when you standing in front of th…

HDU4372 Count the Buildings —— 组合数 + 第一类斯特林数

题目链接:https://vjudge.net/problem/HDU-4372 Count the Buildings Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2509 Accepted Submission(s): 815 Problem Description There are N buildings standin…

HDU 4372 Count the Buildings

Count the Buildings Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2521 Accepted Submission(s): 817 Problem Description There are N buildings standing in a straight line in the City, numbere…

K - Count the Buildings 参考:Count the Buildings 思路可以借鉴,但是代码略有问题写的时候 re 了 9 发,然后把变量定义的顺序换了一下居然 A 了,以为这个是个骚操作,最后才发现是真的会越界,当 f+b>n+2 的时候就有可能会发生越界,而这种情况,if 判断一下就好代码: // Created by CAD on 2019/8/17. #include <bits/stdc++.h> using namespace std; using…

HDU4372 Count the Buildings （+题解：斯特林数）

题面 (笔者翻译) There are N buildings standing in a straight line in the City, numbered from 1 to N. The heights of all the buildings are distinct and between 1 and N. 有n座高楼,从左往右数第 i 座楼的高度为 ai,每座高楼高度互不相同,且 1 ≤ ai ≤ n ,换言之,n座高楼高度形成的序列为1~n的一个排列. You can see…

HDU 4372 Count the Buildings：第一类Stirling数

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4372 题意: 有n栋高楼横着排成一排,各自的高度为1到n的一个排列. 从左边看可以看到f栋楼,从右边看可以看到b栋楼,并且高的楼会挡住低的楼. 问你这些楼有多少种排列方法. 题解: 由于高的楼会挡住低的楼,所以这些楼首先会被划分成f+b-2个区域(除去中间最高的楼),并且左边有f-1个,右边有b-1个. 对于一个区域(假设在左边),这个区域由若干栋楼组成,并且最高的楼一定在最左边. 那么,由一个区域…