Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Example 2: Input: [0,2,3,4,6,8,9] Output: ["0","2->4"…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 我的代码,结果Accepted,507ms: public class Solution { public IList<string>…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: JAVA实现如下: public List<String> summaryRanges(int[] nums) { List…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. class Solution { public: vector<string> summaryRanges(vector<int&…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: 相邻的两个数字若差距为1,则继续向后读,直到不满足条件为止,则把起始到终点的结果表示出来.如此,直到读到数组的最后位置为止.…
Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges. Example: Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99,Output: ["2", "4->49", "51-…
