一.题目说明 这个题目是19. Remove Nth Node From End of List,不言自明.删除链表倒数第n个元素.难度是Medium! 二.我的解答 链表很熟悉了,直接写代码. 性能如下: Runtime: 8 ms, faster than 35.76% of C++ online submissions for Remove Nth Node From End of List. Memory Usage: 8.8 MB, less than 5.26% of C++ onl…

要求 给定一个链表,删除倒数第n个节点 示例 1->2->3->4->5->NULL , n=2 1->2->3->5 边界 n是从0还是从1计 n不合法,负数或者大于链表长度如何处理 思路 遍历一遍计算链表长度,再遍历一遍删除倒数第n个节点 使用两个指针同时移动,找到待删除节点的前一个节点 实现 1 struct ListNode { 2 int val; 3 ListNode *next; 4 ListNode(int x) : val(x), next…

1. 4Sum Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadruplets. Fo…

主要用于记录在LeetCode刷题的过程中学习到的一些思想和自己的想法,希望通过leetcode提升自己的编程素养 :p 高效leetcode刷题小诀窍(这只是目前对我自己而言的小方法,之后会根据自己的切身经历更新): 算法不是纯粹拼智商的,智商高,就一定很厉害,不够聪明,就一定不行.算法是一种技能,是可以通过科学合理的方式训练出来的能力.目前国内大厂的算法考察,基本不会超过leetcode 中等难度,上限难度基本都是leetcode 中等题里面的中等难度 基本的算法数据结构是有限的.比如说链表…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…

Given a linked list, remove the n-th node from the end of list and return its head. Example:                     Given linked list: 1->2->3->4->5, and n = 2.                     After removing the second node from the end, the linked list beco…

题目链接 题目要求: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: ->->->->, and n = . After removing the second node from the end, the linked list becomes ->->->. Note: Given…

题目说明 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: G…

本人算法还是比较菜的,因此大部分在刷基础题,高手勿喷 选择Python进行刷题,因为坑少,所以不太想用CPP: 1.买股票的最佳时期2 给定一个数组,它的第 i 个元素是一支给定股票第 i 天的价格. 设计一个算法来计算你所能获取的最大利润.你可以尽可能地完成更多的交易(多次买卖一支股票). 注意:你不能同时参与多笔交易(你必须在再次购买前出售掉之前的股票). 思路:买高不买低,向上即可 class Solution(object): def maxProfit(self, prices): "…

题目 Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Giv…