题目大意: 给你 1到n ,  n个计算机进行数据传输, 问从1为起点传输到所有点的最短时间是多少, 其实就是算 1 到所有点的时间中最长的那个点. 然后是数据 给你一个n 代表有n个点, 然后给你一个邻接矩阵, 只有一半,另一半自己补 下面是练习的代码. 分别用了Floyd 和 Dijkstra 还有 Spfa(邻接矩阵版) #include <iostream> #include <cmath> #include <cstring> #include <cst…

传送门 MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5711   Accepted: 3552 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierar…

题目大意:求点1到所有点最短路径的最大值 思路:水题,单源最短路,网上解题清一色dijkstra,但是点数小于100显然floyd更简洁嘛 #include<cstdio> #include<string.h> #define maxn 101 #define inf 100000 using namespace std; int read(){ int f=1,x=0;char ch=getchar(); while(ch<'0'||ch>'9'){if(ch=='x…

POJ 1502 MPI Maelstrom / UVA 432 MPI Maelstrom / SCU 1068 MPI Maelstrom / UVALive 5398 MPI Maelstrom /ZOJ 1291 MPI Maelstrom (最短路径) Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shar…

MPI Maelstrom Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 2   Accepted Submission(s) : 1 Problem Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6044   Accepted: 3761 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4017   Accepted: 2412 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

MPI Maelstrom BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to…

题目链接:http://poj.org/problem?id=1502 题意是给你n个点,然后是以下三角的形式输入i j以及权值,x就不算 #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; ; const int INF = 1e9; typedef pair <int , int> P; struct da…

Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to be…

题目: BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5547   Accepted: 3458 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

题目链接:http://poj.org/problem?id=1502 Description BIT has recently taken delivery of their processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has ask…

题目链接:http://poj.org/problem?id=1502 题意:一个处理器给n-1个处理器发送广播,问最短时间.广播时并发,也就是各个路径就大的一方.输入如果是x的话说明两个处理器不能相互通信.输入是矩阵的左三角. 题解:一个最短路的裸题吧.输入的时候注意一下字符的转换.floyd爆一遍之后再对每个路径找最大值即可. 代码: #include<cstdio> #include<cstdlib> #include<cstring> #include<i…

题意 : 给出 N 个点,各个点之间的路径长度用给出的下三角矩阵表示,上上角矩阵和下三角矩阵是一样的,主对角线的元素都是 0 代表自己到达自己不用花费,现在问你从 1 到 N 的最短路,矩阵的 x 代表点间无法互相到达 分析 : 最短路模板…… 就是在输入的时候需要将字符串变成整数.自己写也可以,也可以使用 atoi(char *)函数,其作用是将字符串数组变成整数,复杂度为 O(n) #include<bits/stdc++.h> using namespace std; ; const i…

新的整理版本版的地址见我新博客 http://www.hrwhisper.me/?p=1952 一.Dijkstra Dijkstra单源最短路算法,即计算从起点出发到每个点的最短路.所以Dijkstra常常作为其他算法的预处理. 使用邻接矩阵的时间复杂度为O(n^2),用优先队列的复杂度为O((m+n)logn)近似为O(mlogn) (一)  过程 每次选择一个未访问过的到已经访问过(标记为Known)的所有点的集合的最短边,并用这个点进行更新,过程如下: Dv为最短路,而Pv为前面的顶点.…

链接:http://poj.org/problem?id=1502 MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5249   Accepted: 3237 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed share…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6499   Accepted: 4036 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

XYZZY Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 4154   Accepted: 1185 Description The prototypical computer adventure game, first designed by Will Crowther on the PDP-10 in the mid-1970s as an attempt at computer-refereed fantasy g…

MPI Maelstrom 总时间限制:  1000ms 内存限制:  65536kB 描述 BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor…

floyd/dijkstra/bellmanford/spaf 模板: 1. floyd(不能处理负权环,时间复杂度为O(n^3), 空间复杂度为O(n^2)) floyd算法的本质是dp,用dp[k][i][j]表示以(1....k)为中间点,i, j之间的最短距离为多少,dp[0][i][j]即为原矩阵图. dp[k][i][j]可以由dp[k-1][i][j]转移得到,即不经过 k 点i, j之间的最短距离为多少, 也可以由dp[k-1][i][k]+dp[k-1][k][j]转移得到,即…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12087   Accepted: 7464 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchi…

点我看题目 题意 : 一个司机要从1点到达n点,1点到n点中有一些点有宾馆,司机的最长开车时间不能超过10小时,所以要在10小时之内找到宾馆休息,但是为了尽快的走到n点,问最少可以经过几个宾馆. 思路 : 这个题太狠了,简直不是人做的....可以BFS一下,然后在B之前先D一下能走的路.当然也可以用SPFA+Floyd. #include <stdio.h> #include <string.h> #include <iostream> #include <que…

题目大意:原题链接 给你一张图,初始你在房间1,初始生命值为100,进入每个房间会加上那个房间的生命(可能为负),问是否能到达房间n.(要求进入每个房间后生命值都大于0) 解题思路: 解法一:Floyd+Bellman 1.Floyd先判断图是否连通,不连通则直接失败 2.Bellman Ford然后跑最长路,判断是否有正环或者有正通路 #include<cstdio> #include<cstring> using namespace std; ],d[]; ][],link[]…

本来我是想把这两个算法分开写描述的,但是SPFA其实就是Dijkstra的稀疏图优化,所以其实代码差不多,所以就放在一起写了. 因为SPFA是Dijkstra的优化,所以我想来讲讲Dijkstra. 什么是Dijkstra Dijkstra是一种求单源最短路的基础算法,时间复杂度在不加堆优化的情况下是o(n^2)的,加了堆优化就能简化到o(nlogn),而且算法稳定性很强(从这点上来说比SPFA好多了,具体怎么好下面再讲),基础思路如下: 首先,把所有点到源的距离设为最大,然后把源加入队列,接着…

poj 2049(二分+spfa判负环) 给你一堆字符串,若字符串x的后两个字符和y的前两个字符相连,那么x可向y连边.问字符串环的平均最小值是多少.1 ≤ n ≤ 100000,有多组数据. 首先根据套路,二分是显然的.然后跑一下spfa判断正环就行了. 然而我被no solution坑了十次提交.. #include <cctype> #include <cstdio> #include <cstring> using namespace std; const in…

POJ-1502 MPI Maelstrom 迪杰斯特拉+题解 题意 题意:信息传输,总共有n个传输机,先要从1号传输机向其余n-1个传输机传输数据,传输需要时间,给出一个严格的下三角(其实就是对角线之下的不包括对角线的部分)时间矩阵,a[i][j]代表从i向j传输数据需要的时间,并规定数据传输之间并无影响,即第一个传输机可以同时向其余传输机传输数据.求所有所有的机器都收到消息(他们收到消息后也可以传输)所需的最短时间. 解题思路 这个可以用迪杰斯特拉来求第一台机器到其他所有机器传输消息的时间,…

#include<cstdio> #include<cstdlib> #include<cstring> #include<iostream> using namespace std; ; const int INF = 0x3f3f3f3f; ]; int n; int f[N][N]; void init() { ; i <= n ; i++) ; j <= n ; j++) if(i == j) f[i][j] = ; else f[i][…

题目链接:https://vjudge.net/problem/POJ-1502 dijkstra板子题,题目提供下三角情况,不包含正对角线,因为有题意都为0,处理好输入,就是一个很水的题. #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> #include <string> #include <vector> using nam…

几个最短路径算法的比较:Floyd 求多源.无负权边(此处错误?应该可以有负权边)的最短路.用矩阵记录图.时效性较差,时间复杂度O(V^3).       Floyd-Warshall算法(Floyd-Warshall algorithm)是解决任意两点间的最短路径的一种算法,可以正确处理有向图或负权的最短路径问题. Floyd-Warshall算法的时间复杂度为O(N^3),空间复杂度为O(N^2). Floyd-Warshall的原理是动态规划:设Di,j,k为从i到j的只以(1..k)集合…