283. Move Zeroes var moveZeroes = function(nums) { var num1=0,num2=1; while(num1!=num2){ nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0); } num1 = nums ; }); nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0);…

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 ->…

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like following: 4 -> 5 -> 1 -> 9 Example 1: Input: head = [4,5,1,9], node = 5 Output:…

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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 ->…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 设置当前节点的值为下一个 日期 [LeetCode] 题目地址:https://leetcode.com/problems/delete-node-in-a-linked-list/ Total Accepted: 78258 Total Submissions: 179086 Difficulty: Easy 题目描述 Write a functio…

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. Example: Input: [0,1,0,3,12] Output: [1,3,12,0,0] Note: You must do this in-place without making a copy of the array…

Description Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. Example: Input: [,,,,] Output: [,,,,] Note: You must do this in-place without making a copy of the array…

------------------------------------------------ 因为不知道前序是谁,所以只好采用类似于数组实现的列表移动值, 又因为如果当前是最后一个元素了但是已经没办法修改前序了所以必须在倒数第二个就修改,所以应该提前进行判断 AC代码: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x)…

Java实现如下: public class Solution { public void deleteNode(ListNode node) { if(node==null||node.next==null) return; node.val = node.next.val; node.next = node.next.next; } }…