Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…
题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4 Output:1->1->2->3->4->4 思路 思路一:建立一个新链表 建立一个新的链表,用…
①英文题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 ②中文题目 将两个有序链表合并为一个新的有序…
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ListNode dumy = new ListNode(0); Li…
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析:合并两个有序序列,这个归并排序中的一个关键步骤.这里是要合并两个有序的单链表.由于链表的特殊性,在合并时只需要常量的空间复杂度. 编码: public ListNode mergeTwoLists(Li…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 注意题目要求合并的时候不能新建节点,直接使用原来的节点,比较简单,代码如下: /** * Definition for singly-linked list. * struct ListNode { * int va…
题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4; 2->6 ] Output:1->1->2->3->4->4->5->6 思路 思路1:堆排序 最小堆 优先队列 思路2:分冶法 Tips 1…
Level: Hard 题目描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 思路分析: 思路一:通过归并排序思想,将k个排好…