HDU 4308 Contest 1

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纯BFS+优先队列扩展. #include <iostream> #include <cstdio> #include <cstring> #include <string.h> #include <queue> using namespace std; bool vis[5100]; char str[5100]; struct point{ int x,y; int cost; bool operator < (const point…

HDU 4308 BFS Saving Princess claire_

原题直通车:HDU 4308 Saving Princess claire_ 分析: 两次BFS分别找出‘Y’.‘C’到达最近的‘P’的最小消耗.再算出‘Y’到‘C’的最小消耗,比较出最小值代码: #include<iostream> #include<cstdio> #include<cstring> #include<queue> #include<string> using namespace std; const int inf=0xF…

hdu 4308 Saving Princess claire_

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4308 Saving Princess claire_ Description Princess claire_ was jailed in a maze by Grand Demon Monster(GDM) teoy.Out of anger, little Prince ykwd decides to break into the maze to rescue his lovely Prince…

Saving Princess claire_（hdu 4308 bfs模板题）

http://acm.hdu.edu.cn/showproblem.php?pid=4308 Saving Princess claire_ Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2305 Accepted Submission(s): 822 Problem Description Princess claire_ wa…

HDU 5045 Contest(状压DP）

Problem Description In the ACM International Collegiate Programming Contest, each team consist of three students. And the teams are given 5 hours to solve between 8 and 12 programming problems. On Mars, there is programming contest, too. Each team c…

hdu - 5045 - Contest（国家压缩dp）

意甲冠军:N个人M通过主打歌有自己的期望,每个问题发送人玩.它不能超过随机播放的次数1,追求最大业绩预期 (1 ≤ N ≤ 10,1 ≤ M ≤ 1000). 主题链接:pid=5045" target="_blank">http://acm.hdu.edu.cn/showproblem.php?pid=5045 -->>设dp[i][j]表示已出战了前i - 1道题目,已出战的人的状态序列为j,如今要做第i道题目的最大期望.则最后要求的结果为max{dp[…

[ACM] hdu 5045 Contest (减少国家Dp）

Contest Problem Description In the ACM International Collegiate Programming Contest, each team consist of three students. And the teams are given 5 hours to solve between 8 and 12 programming problems. On Mars, there is programming contest, too. Each…