LeetCode题解之Rotated Digits

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LeetCode题解之Rotated Digits

1.题目描述 2.代码 int rotatedDigits(int N) { ; ; i <= N; i++) { if (isGood(i)) { res++; } } return res; } bool isGood(int x) { int rx = x; vector<int> nums; while (x) { ; nums.push_back(r); x = x / ; } for (vector<int>::iterator it = nums.begin()…

LeetCode算法题-Rotated Digits（Java实现）

这是悦乐书的第316次更新,第337篇原创 01 看题和准备今天介绍的是LeetCode算法题中Easy级别的第185题(顺位题号是788).如果一个数字经过180度旋转后,变成了一个与原数字不同的数,这样的数被称为好数字.数字中的每一位都必须经过旋转.旋转的规则是:0,1,8这三个数旋转后还是自身,2旋转后变为5,5旋转后变为2,6旋转后变为9,9旋转后变为6,剩下的3,4,7旋转后并不能转成其他数字,是无效的.现在给出正数N,从1到N的好数字一共有多少个?例如: 输入:10 输出:4 说明…

【LeetCode】788. Rotated Digits 解题报告（Python）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法日期题目地址:https://leetcode.com/problems/rotated-digits/description/ 题目描述 X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that i…

LeetCode 题解之Add Digits

1.问题描述 2.问题分析循环拆分数字,然求和判断. 3.代码 int addDigits(int num) { ) return num; int result = num; do{ vector<int> r = splitnum( result ); result = ; for(auto & n : r ){ result += n; } } ); return result ; } vector<int> splitnum( int num ){ vector&…

73th LeetCode Weekly Contest Rotated Digits

X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. A number is valid if each digit remains a digit after rotation. 0, 1, and 8 rotate to themselves; 2 and 5 rotate to each othe…

[LeetCode 题解] Search in Rotated Sorted Array

前言 [LeetCode 题解]系列传送门: http://www.cnblogs.com/double-win/category/573499.html 题目描述 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target…