lc49 Group Anagram 逻辑很简单,就是统计字母出现次数,然后将完全相同的字符串放入同一list 关键是怎么实现 统计的部分,可以通过将string排序,Arrays.sort(),或者像之前int[26]一样, 那么如何一次遍历,就能将相同字符串放入一个list呢? 这里用到了HashMap<String, List<String>>,String为key,用来判断排序过后的str是否相同,若是相同,直接原来的str加入List<String> 最后返回…

Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat",…

49. Group Anagrams Problem's Link ---------------------------------------------------------------------------- Mean: 给定一个由string类型构成的集合,让你按照每个字符串的单词构成集合来将这个集合分类. analyse: STL的运用. Time complexity: O(N) view code /** * ---------------------------------…

https://leetcode.com/problems/anagrams/ Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat&q…

Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ["nat","…

题目链接: https://leetcode.com/problems/anagrams/?tab=Description   Problem:给一个字符串数组,将其中的每个字符串进行分组,要求每个分组中的各个字符串所包含的字母都相同对字母的前后顺序没有要求!       使用 Map<String, List<String>> map 进行求解   给定的字符串数组为 String[] strs 1.当strs为空时返回new ArrayList<List<Strin…

Given an array of strings, group anagrams together. Example: Input: ["eat", "tea", "tan", "ate", "nat", "bat"], Output: [ ["ate","eat","tea"], ["nat","…

是之前的重排列字符串的延伸,判断是重排列后存到HashMap中进行分组 这种HashMap进行分组的方式很常用 public List<List<String>> groupAnagrams(String[] strs) { /* 其实重排列的那个题是有两种做法的,之前整理的是比较好的的一种字母哈希表的方法,还有一种方法 是把字符串排序,然后进行比较就行. 这个题正好就是用了排序的方法,排序后的字符串作为key,list作为value就行 一开始想用字母哈希表的方法,结果没做出来…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

LeetCode 49: 字母异位词分组 Group Anagrams 题目: 给定一个字符串数组,将字母异位词组合在一起.字母异位词指字母相同,但排列不同的字符串. Given an array of strings, group anagrams together. 示例: 输入: ["eat", "tea", "tan", "ate", "nat", "bat"], 输出: [ […