104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…

105. Div 3 time limit per test: 0.25 sec. memory limit per test: 4096 KB There is sequence 1, 12, 123, 1234, ..., 12345678910, ... . Given first N elements of that sequence. You must determine amount of numbers in it that are divisible by 3. Input In…

题目 http://poj.org/problem?id=1157 题目大意 有f个花,k个瓶子,每一个花放每一个瓶子都有一个特定的美学值,问美学值最大是多少.注意,i号花不能出如今某大于i号花后面.问最大美学值是多少 解题思路 dp[i][j]表示将第i个花插入第k个瓶子的最大美学值. 状态转移方程为dp[i][j] = max(dp[i-1][(i-1)~(k-f+i-1)]) + value[i][j] 代码 #include <cstdio> const int maxn = 110;…

题目 https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1903 题意 一棵树,根上有VOD站,要求任意叶节点到VOD站的距离不超过k,问最少建新VOD站数. 思路 1. 令vod[i]为节点i到VOD站的最短距离,  注意,这是在以i为根的树上有VOD站的情况下,如果没有,vod[i]就设为非法. 依据树形DP的思路,如果在该…

Domination Time Limit: 8 Seconds      Memory Limit: 131072 KB      Special Judge Edward is the headmaster of Marjar University. He is enthusiastic about chess and often plays chess with his friends. What's more, he bought a large decorative chessboar…

D. Bag of mice time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The dragon and the princess are arguing about what to do on the New Year's Eve. The dragon suggests flying to the mountains t…

143. Long Live the Queen time limit per test: 0.25 sec. memory limit per test: 4096 KB The Queen of Byteland is very loved by her people. In order to show her their love, the Bytelanders have decided to conquer a new country which will be named accor…

http://acm.timus.ru/problem.aspx?space=1&num=1203 按照结束时间为主,开始时间为辅排序,那么对于任意结束时间t,在此之前结束的任务都已经被处理,从这个时间开始的任务都正要被处理, 因为t<=3e5,可以用简单dp解决 #include <cstdio> #include <algorithm> using namespace std; const int maxn=1e5+5; int n; typedef pair&l…

http://acm.hdu.edu.cn/showproblem.php?pid=4405 明显,有飞机的时候不需要考虑骰子,一定是乘飞机更优 设E[i]为分数为i时还需要走的步数期望,j为某个可能投出的点数如果从i向i-j推导,我们并不能确定i的转移方向,因为可能有两个i-j有飞机其目的地是i,所以我们选择从i向i+j推导期望 如果设G[i]为分数为i时已经走过的步数期望,那么要确定G[i+j]需要知道P(i|i+j),也即转移到i+j的条件下从i转移来的概率,比较麻烦 由题意,设match…

题目 http://poj.org/problem?id=1837 题意 单组数据,有一根杠杆,有R个钩子,其位置hi为整数且属于[-15,15],有C个重物,其质量wi为整数且属于[1,25],重物与重物之间,钩子与钩子之间彼此不同.忽略杠杆及重心的影响,有多少种方式使得全部重物都挂上钩子(某些钩子可能挂若干个重物)后杠杆平衡? 思路 由于状态比较小,即使n的五次方也足以承受,而且任意时刻杠杆的状态在[-15 * 25 * 20, 15 * 25 * 20]之间,所以可以直接穷举状态. 感想…