B. Chocolate time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the…

B. Wet Shark and Bishops time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 t…

B. Wet Shark and Bishops time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input output: standard output Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from…

Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 to 1000. Rows are numbered from top to bottom, while columns are numbered from left to right. Wet Shark thinks that two bishops attack e…

题意:处在同一对角线上的主教(是这么翻译没错吧= =)会相互攻击 求互相攻击对数 由于有正负对角线 因此用两个数组分别保存每个主教写的 x-y 和 x+y 然后每个数组中扫描重复数字k ans加上kC2就行了 wa了两发的原因是没考虑到如果整个数组都是重复的 那要最后额外加一次 #include <cstdio> #include <cmath> #include <cstring> #include <queue> #include <vector&…

题 题意 1000*1000的格子里,给你n≤200 000个点的坐标,求有多少对在一个对角线上. 分析 如果求每个点有几个共对角线的点,会超时. 考虑到对角线总共就主对角线1999条+副对角线1999条,我们可以求每个对角线有几对点. 同一条主对角线上的元素有a[i]个,就有C(a[i],2)对点: 同一条副对角线上的元素有b[i]个,就有C(b[i],2)对点. 读入x和y后, x+y相同的就在同一副对角线,x+y范围是(2,2000), x-y相同的就是同一主对角线,x-y范围是(-999…

对角线 x1+y1=x2+y2 或者x1-y1=x2-y2 #include<iostream> #include<string> #include<algorithm> #include<cstdlib> #include<cstdio> #include<set> #include<map> #include<vector> #include<cstring> #include<stack…

记录一下每个对角线上有几个,然后就可以算了 #include<cstdio> #include<cstring> #include<cmath> #include<ctime> #include<vector> #include<algorithm> using namespace std; +; int n; long long w1[maxn]; long long w2[maxn]; long long ans; int mai…

 B. Wet Shark and Bishops time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Today, Wet Shark is given n bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from…

题 Today, Wet Shark is given n integers. Using any of these integers no more than once, Wet Shark wants to get maximum possible even (divisible by 2) sum. Please, calculate this value for Wet Shark. Note, that if Wet Shark uses no integers from the n …