Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative.     各个位相乘,保存在数组中,最后再处理进位. 如 123*456     4,5,6      8,10,12         12,15,18…

转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…

题目要求:Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 分析: 参考网址:http://blog.csdn.net/pickless/article/details/9235907 利用竖式的思想,…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路一: BigInteger!!! JAVA实现如下: import java.math.BigInteger; public class Solution { static pu…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:直观思路,就是模拟乘法过程.注意进位.我写的比较繁琐. string multiply(string num1, string num2) { vector<int> v1, v…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 第一眼看到这个题目,潜意识里觉得直接将字符串转换为数字相乘,然后将结果再转换为字符串,难道这题考的是字符串与数值之间的转换? 细看,发现数字可能非常大,那么问题来了:这个数据类型怎么定义…

题目描述: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路: 设置数组记录单个位置相乘的结果,最后负责相加进位. 代码如下: public class Solution { public String multiply(St…

题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意给两个字符串表示的数字,计算他们的乘积. 其实就是手写一个大数乘法,先翻转字符串便于从低位开始计算. 模拟乘法的运算过程,把中间结果存在data中,最后在考虑data的进位并…

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…

题目链接: https://leetcode.com/problems/multiply-strings/?tab=Description     求解大数相乘问题   按照上图所示,进行嵌套循环计算.每次计算出两个位置上的数字,并且对其求和进行更新操作. 下面这个讲解很赞!!! https://discuss.leetcode.com/topic/30508/easiest-java-solution-with-graph-explanation/3      参考代码:  package l…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT use internal library su…

感觉是大数相乘算法里面最能够描述.模拟演算过程的思路 class Solution { public String multiply(String num1, String num2) { if(num1.charAt(0) == '0' || num2.charAt(0) == '0'){ return "0"; } int len1 = num1.length(); int len2 = num2.length(); int len = len1+len2; int[] arr =…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题目意思: 给两个string,计算string的乘积. string中的数可以非常大并且是非负数. (就是大数的乘法运算嘛...) 解题思路: 由于之…

1 题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 接口: public String multiply(String num1, String num2); 2 思路 大整数的乘法,不能够简单用Integer.valueOf(…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 43: Multiply Stringshttps://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbit…

这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…

1. Combination Sum Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. No…

43. 字符串相乘 43. Multiply Strings 题目描述 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. LeetCode43. Multiply Strings中等 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456&q…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 将乘积逐位逆序存放在int数组result中. 记num1当前为第i位,num2当前为第j位,则乘积存放在result[(n1-1-i)+(n2-1-j…

Multiply StringsGiven two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. SOLUTION 1: 参考自http://blog.csdn.net/fightforyourdream/article/details/1737049…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Permutation Sequence The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" &q…

http://www.cnblogs.com/TenosDoIt/p/3735309.html https://blog.csdn.net/fly_yr/article/details/48055617 class Solution { public: string multiply(string num1, string num2) { int len1 = num1.length(); int len2 = num2.length(); vector<); ; 第一轮乘出来的结果只有len1…

Leetcode练习题Remove Element Question: Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

https://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. class Solution { public: string multiply(stri…

一天一道LeetCode系列 (一)题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT us…

原题地址:https://oj.leetcode.com/problems/multiply-strings/ 题意: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路:两个非负数字字符串的相乘.其实就是大数乘法.算法的关键是…