Box Relations Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 894    Accepted Submission(s): 324Special Judge Problem Description There are n boxes C1, C2, ..., Cn in 3D space. The edges of the…

题目大意: 给定一些正方体的关系,要求一组符合这些关系的正方体坐标,如果不存在符合条件的正方体坐标,IMPOSSIBLE.(Special Judge) 实力还是太弱了,完全不会…… #include <cstdio> #include <stdlib> #include <iostream> #define MAXN 2010 #define MAXR 500000 #define MAX 999999 typedef struct edges{ int v,w,ne…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3231 题意:有n个长方体,四种限制条件.(1)I x y x和y有相交:(2)X/Y/Z  x y x的最大X/Y/Z坐标小于y的最大X/Y/Z.构造出这样的n个长方体. 思路:首先,XYZ三个方向是可以分开考 虑的.那么我们可以一个个分别求解.将每个长方体拆成左上角右下角两个点,我们假设现在考虑X方向,也即是一个长方体对应两个X方向的点,共2*n个点, 边<i,j>表示i小于j,那么首先有边&l…

HDU3231 Box Relations 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3231 题目意思:在一个三维空间上有一些棱和坐标轴平行的立方体.给够给予四种关系.I i j表示i,j两个立方体是有部分的重合,X i j表示立方体i所有点x坐标都小于立方体j的x坐标,Y i j表示立方体i所有点y坐标都小于立方体j的y坐标,Z i j表示立方体i所有点Z坐标都小于立方体j的Z坐标.然后给出一系列这样的关系,问你这些关系是否存在矛盾,如果不…

Box Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) [Problem Description] There are N boxes on the ground, which are labeled by numbers from 1 to N. The boxes are magical, the size of each one can be enlarged or r…

http://acm.hdu.edu.cn/showproblem.php?pid=2088 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. “Look, I've built a wall!”, he tells his older sister Alice…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2088 Box of Bricks Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 20219    Accepted Submission(s): 6473 Problem Description Little Bob likes playi…

Box Time Limit: 5000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 247564-bit integer IO format: %I64d      Java class name: Main There are N boxes on the ground, which are labeled by numbers from 1 to N. The boxes are magi…

本文索引目录: 一.贪心算法的基本思想以及个人理解 二.汽车加油问题的贪心选择性质 三.一道贪心算法题点拨升华贪心思想 四.结对编程情况 一.贪心算法的基本思想以及个人理解: 1.1 基本概念: 首先我们从课本中仔细品读基本的贪心概念,顾名思义,贪心算法总是作出在当前看来最好的选择.也就是说贪心算法并不从整体最优考虑,它所作出的选择只是在某种意义上的局部最优选择.当然,希望贪心算法得到的最终结果也是整体最优的.虽然贪心算法不能对所有问题都得到整体最优解,但对许多问题它能产生整体最优解.如单源最短…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1326 题目大意: 给n堵墙,每个墙的高度不同,求最少移动多少块转使得墙的的高度相同. 解题思路: 找到平均墙的高度(即最后墙的高度),遍历所有墙,如果小于平均墙,则用平均墙减去高度即是要移动的高度,统计所有需要"补"的高度即可.注意输出. AC Code: #include<bits/stdc++.h> using namespace std; int main() { ; w…

Problem Description One day, winnie received a box and a letter. In the letter, there are three integers and five operations(+,-,*,/,%). If one of the three integers can be calculated by the other two integers using any operations only once.. He can…

Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. "Look, I've built a wall!", he tells his older sister Alice. "Nah, you should make all stacks th…

版权声明:本文为博主原创文章,未经博主允许不得转载. hdu 2475 Splay树是一种神奇的东西... 题意: 有一些箱子,要么放在地上,要么放在某个箱子里面 . 现在有两种操作: (1) MOVE x y: 把 x 号箱子放到 y 号箱子里面,操作不合法就忽略这一次操作 . (2) QUERY x :  查询 x 号箱子最外面的箱子是哪一个 解法: 首先对所有的树进行一遍DFS,得到一个DFS序,可以把它看成是一个括号序列,开始访问某个节点是左括号,结束访问时是右括号 .这样这题就转换成用…

Little Bob likes playing with his box of bricks. He puts the bricks one upon another and builds stacks of different height. ``Look, I've built a wall!'', he tells his older sister Alice. ``Nah, you should make all stacks the same height. Then you wou…

题目大意: N个盒子 给你K个以下关系 1.A和B有重叠 2.A在B的左边且不重叠 3.A在B的前边且不重叠 4.A在B的上面且不重叠 显然单独分配X坐标处理2(x1<x2<x1'<x2'),Y坐标处理3(同上),Z坐标处理4(同上). 1操作怎么处理? X,Y,Z都要处理,A和B 要重叠  必须X,Y,Z都符合夹着的样 (x1<x2'&&x1'<x2)(y,z同理) 所以就是给你很多x1,x2,y1,y2,z1,z2关系 求满足关系的东西,查分约束,或这里直…

树型转线型.第一次听说这个概念. . . , 可是曾经已经接触过了,如LCA的预处理部分和树链剖分等.可是没想到还能这么用,三者虽说有不同可是大体思想还是非常相近的,学习了. 推荐博客http://blog.csdn.net/lyhypacm/article/details/6734748 转成线型之后.就变成了伸展树的模板题. 另外要注意,伸展树的特点是平均时间复杂度接近log(n).所以一定要记得每次操作之后都要伸展.再次学习了. #include <algorithm> #include…

HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…

Box Relations Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1334    Accepted Submission(s): 540Special Judge Problem Description There are n boxes C1, C2, ..., Cn in 3D space. The edges of the…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1110 Equipment Box Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2989    Accepted Submission(s): 759 Problem Description There is a large room in…

http://acm.hdu.edu.cn/showproblem.php?pid=1732 推箱子和游戏规则一样. #include <cstdio> #include <cstring> #include <queue> #include <algorithm> using namespace std; ][]; int n,m; int sx,sy; ][][][][][][][]; ][]= {{,},{,-},{,},{-,}}; struct n…

There are N boxes on the ground, which are labeled by numbers from 1 to N. The boxes are magical, the size of each one can be enlarged or reduced arbitrarily. Jack can perform the “MOVE x y” operation to the boxes: take out box x; if y = 0, put it on…

Box \[ Time Limit: 5000 ms \quad Memory Limit: 32768 kB \] 题意 给出 \(n\) 个箱子的包含关系,每次两种操作. 操作 \(1\):把 \(x\) 的箱子及里面的箱子一块挪到 \(y\) 箱子里面去. 操作 \(2\):查询 \(x\) 箱子的最外层的箱子编号. 思路 对于每一大块箱子,可以看成树和子树的包含关系,那么可以根据树的 \(dfs\) 序,把一个箱子所包含的箱子拍成一个区间,这样就变成了很多颗树.为了方便后面的操作,对于每…

题意:nxm的棋盘,要求每行每列至少放一个棋子的方法数. 解法:首先可以明确是DP,这种行和列的DP很多时候都要一行一行的推过去,即至少枚举此行和前一行. dp[i][j]表示前 i 行有 j 列都有了棋子,且每行也有棋子. 这题做法: 从第1行到第n行,枚举这一行有k列已至少有一个,再枚举前一行有j列至少有一个,然后枚举这一行新放多少个棋子t,至少一个(因为每行至少一个) 那么有 dp[i][k] += dp[i-1][j]*C[m-j][k-j]*C[j][t-(k-j)], C表示组合数…

题目链接:https://vjudge.net/problem/HDU-5155#author=0 题意:在一个n*m的方格中要满足每一行每一列至少有一个珠宝,问总共有多少种方案. 思路:利用递推的思想:dp[i][j]表示前i行前j列满足条件的个数,那么如果说前i行前j-1列已经满足条件了那么第j列可以放[1,n]个那么dp[i][j]=dp[i][j-1]*(2^n-1);因此假设前i行j-1列有k行还没放珠宝那么 dp[i][j]=dp[i-k][j-1]*C(i,k)*(C(i-k,0)…

Box of Bricks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5994    Accepted Submission(s): 2599 Problem Description Little Bob likes playing with his box of bricks. He puts the bricks one up…

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=3449  Consumer Description FJ is going to do some shopping, and before that, he needs some boxes to carry the different kinds of stuff he is going to buy. Each box is assigned to carry some specifi…

Reference:http://www.cnblogs.com/wuyiqi/archive/2012/03/28/2420916.html 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=2836 题目大意:计算序列有多少种组合,每个组合至少两个数,使得组合中相邻两个数之差不超过H,序列有重复的数.MOD 9901. 解题思路: 朴素O(n^2) 以样例1 3 7 5为例,如果没有重复的数. 设dp[i]前n个数的方案数,初始化为1. 那么fo…

 Balls and Boxes(盒子与球) Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Description 题目描述 Mr. Chopsticks is interested in random phenomena, and he conducts an experiment to study randomness. In the experiment, he thr…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=3288 Resource Allocation Description HDU-Sailormoon is made up of three girls~~~wj, xq, lff, usually they work together ---- solve a variety of problems. So they has to use some resources in the process.…

最少拦截系统 Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1257 Appoint description:  System Crawler  (2015-09-07) Description 某国为了防御敌国的导弹袭击,发展出一种导弹拦截系统.但是这种导弹拦截系统有一个缺陷:虽然它的第一发炮弹能够到达任意的高度,但是以后每一发炮弹都…