Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1217 题目大意 在每种钱币间进行各种交换,最后换回自己如果能赚,那么就Yes,否则No 注意应为有负权所以dijsktra在这里行不通了可以用国产的spfa算法,可比bfs. 我的AC代码 #include<iostream>#include<cstdio>#include<cstring>#include<map>#include<queue>us…

hdu1217 Arbitrage Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4123    Accepted Submission(s): 1878 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to tr…

题目大意: 给你几种货币,以及几种汇率关系,问是否存在套利的可能? 思路: 初步想法:图上存在一个环的路径上权值相乘大于1.... 再者:该如何找到图上所有环呢.... 好吧 经过鸟神 和 况神的指点,,,这题就是一道floyed求最小环而已(权重取负)(虽然差不多,其实还是差挺远..) 对于乘法处理转换为ln...Orz一下鸟神 Floyed求最小环(后来才发现没关系) 一开始天真的以为.....只要求一遍Floyed 再判断一下F[i][i]就好,但要记住这个图是带负权值的....所以可能是…

汇率转换问题: 怎么样才能套利 可以用Floyd算法: #include<bits/stdc++.h> using namespace std; ][]; int main() { int n,m; map<; ,n) { string ss; ;i<=n;i++) { cin>>ss; ma[ss]=i; } string s1,s2;double rate; ;i<=n;i++) ;j<=n;j++) { ; ; } scanf("%d&quo…

POJ 2240 Arbitrage / ZOJ 1092 Arbitrage / HDU 1217 Arbitrage / SPOJ Arbitrage(图论,环) Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For exa…

Time Limit: 1000 MS Memory Limit: 65536 KB 64-bit integer IO format: %I64d , %I64u   Java class name: Main [Submit] [Status] [Discuss] Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency in…

题目来源:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=40  Arbitrage  Background The use of computers in the finance industry has been marked with controversy lately as programmed tr…

Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16652   Accepted: 7004 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currenc…

题目传送门 /* 最短路:Floyd模板题 只要把+改为*就ok了,热闹后判断d[i][i]是否大于1 文件输入的ONLINE_JUDGE少写了个_,WA了N遍:) */ #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #include <string> #include <map> #include <cmath>…

Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15640   Accepted: 6563 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currenc…

原题链接 题目大意:Arbitrage这个单词的解释是“套利交易”,就是利用几个币种之间的汇率差价来赚钱.比如人民币兑美元6:1,美元兑欧元1.5:1,欧元兑人民币10:1,那么用9元人民币可以换1.5美元,1.5美元换1欧元,1欧元换10元人民币.这样一倒手,就赚了1元.这是闷声发大财的典型例子! 解法:在做这道题的时候,又学会了一种新的算法(Floyd算法).具体过程是开辟一个方阵,每行每列都对应一种货币,每个元素就是横纵两种货币的汇率.然后是一个三层循环,最外层的循环是表示过度节点的,这一…

点击打开链接 Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13434   Accepted: 5657 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same…

Arbitrage http://acm.hdu.edu.cn/showproblem.php?pid=1217 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that…

Arbitrage 题目链接: http://acm.hust.edu.cn/vjudge/contest/122685#problem/I Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose…

Arbitrage DescriptionArbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys…

三道题都是考察最短路算法的判环.其中1860和2240判断正环,3259判断负环. 难度都不大,可以使用Bellman-ford算法,或者SPFA算法.也有用弗洛伊德算法的,笔者还不会SF-_-…… 直接贴代码. 1860 Currency Exchange: #include <cstdio> #include <cstring> int N,M,S; double V; ; int first[maxn],vv[maxn*maxn],nxt[maxn*maxn]; double…

Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 Fre…

Arbitrage                                              Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)                                               Total Submission(s): 3180    Accepted Submission(s): 1445 Problem…

题意  给你n种币种之间的汇率关系  推断是否能形成套汇现象  即某币种多次换为其他币种再换回来结果比原来多 基础的最短路  仅仅是加号换为了乘号 #include<cstdio> #include<cstring> #include<string> #include<map> using namespace std; map<string, int> na; const int N = 31; double d[N], rate[N][N],…

描述Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 French francs…

Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 Fre…

Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:27167   Accepted: 11440 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currenc…

Dijkstra算法是处理单源最短路径的有效算法,但它局限于边的权值非负的情况,若图中出现权值为负的边,Dijkstra算法就会失效,求出的最短路径就可能是错的. 这时候,就需要使用其他的算法来求解最短路径,Bellman-Ford算法就是其中最常用的一个. 由于此题中需要求的是有一种货币A,通过一系列的转化,能够再次转化回A,因此,运用bellman算法来解决此题. 具体的关于bellman最短路的求法请见转载博客:http://www.cnblogs.com/aiguona/p/722653…

Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 Fre…

Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 21300   Accepted: 9079 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currenc…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1217 /************************************************************************/ /* hdu Arbitrage floyd求最短路径 题目大意:floyd算法,求得两点之间最短距离,(u,v) = min( (u,v),(u,w)+(w,v) ); 此题,是求其能够赚钱,即最大生成树,且过程是相乘的,公式:( u, v) =…

Time Limit: 1000MS Memory Limit: 65536K Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 Brit…

链接: http://poj.org/problem?id=2240 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22010#problem/F Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13067   Accepted: 5493 Description Arbitrage is the use of discrepancies i…

Arbitrage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 29374   Accepted: 12279 题目链接:http://poj.org/problem?id=2240 Description: Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into…