地址:http://acm.hdu.edu.cn/showproblem.php?pid=1025 题目: Problem Description JGShining's kingdom consists of 2n(n is no more than 500,000) small cities which are located in two parallel lines. Half of these cities are rich in resource (we call them rich…

分析: 最长不降子序列,n很大o(n^2)肯定超,想到了小明序列那个题用线段树维护前面的最大值即可 该题也可用二分搜索来做. 注意问题输出时的坑,路复数后加s #include <map> #include <set> #include <list> #include <cmath> #include <queue> #include <stack> #include <cstdio> #include <vecto…

Constructing Roads In JGShining's Kingdom  HDU1025 题目主要理解要用LCS进行求解! 并且一般的求法会超时!!要用二分!!! 最后蛋疼的是输出格式的注意(直接报错误!!!) #include<iostream> #include<stdio.h> #include<algorithm> #include<string.h> using namespace std; ],dp[]; int main() { ,…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14635    Accepted Submission(s): 4158 Problem Description JGShining's kingdom consists of 2n(n is no mo…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23467    Accepted Submission(s): 6710 Problem Description JGShining's kingdom consists of 2n(n is no mo…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16047    Accepted Submission(s): 4580 Problem Description JGShining's kingdom consists of 2n(n is no mor…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21002    Accepted Submission(s): 5935 Problem Description JGShining's kingdom consists of 2n(n is no mor…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13646    Accepted Submission(s): 3879 Problem Description JGShining's kingdom consists of 2n(n is no mor…

HDOJ(HDU).1025 Constructing Roads In JGShining's Kingdom (DP) 点我挑战题目 题目分析 题目大意就是给出两两配对的poor city和rich city,求解最多能修几条不相交的路.此题可以转化为LIS问题.转化过程如下: 数据中有2列,为方便表述,暂且叫做第一列和第二列. 1.若第一列是是递增的(给出的2个样例都是递增的),那么要想尽可能多的做连线,则那么就需要找出第二列中最长的递增子序列,若出现非递增的序列,那么连线后一定会相交.…

题目链接: Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)     Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21045    Accepted Submission(s): 5950 Problem Description JGShining's kingdom consists of 2n(n is…