也是一个简单剪枝的dfs.记录所有为0的位置,依次填写,当发现某个空格可选的填写数字已经没有时,说明该支路无效,剪掉. 不算是一个难题吧,但是还是花了不少时间,问题主要出在细节上,行列坐标反了.3乘3小格的位置判断等.写程序一定要细心. #include <iostream> using namespace std; ; ][MAX_R + ]; ]; ]; int zero_cnt; int setPossibleDigits(int x, int y, int s) { ]; memset…
Sudoku Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 24081 Accepted: 11242 Special Judge Description Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure.…
Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character '.'. You may assume that there will be only one unique solution. A sudoku puzzle... ...and its solution numbers marked in red. 这道求解数独的题是在之…
Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules. The Sudoku board could be partially filled, where empty cells are filled with the character '.'. A partially filled sudoku which is valid. Note:A valid Sudoku board (partially…
数独游戏的规则从很久之前就知道,但是一直都没怎么玩过,然后到了大学,大一下学期自己学dfs的时候,刚刚好碰到了一个数独的题目,做出来后,感觉还是挺有成就感的 然后大二学了JAVA,看了下那个一些有关于界面的一些函数的使用这些,就写出来一个比较粗糙的数独游戏,这个游戏我打算一直维护更新,直到我大学毕业,看看最后可以变成什么样子 public class Main { public static void main(String[] args) { gra f = new gra("数独"…