leetcode87. Scramble String 题意: 给定一个字符串s1,我们可以通过将它分解为两个非空子字符串来表示为二叉树. 思路: 递归解法 对于每对s1,s2. 在s1某处切一刀,s1分成left,right,然后在s2首部开始等长的地方切一刀,切成left,right.只要s1的left和s2的left,s1的right和s2的right同样也构成scramble string就可以了. 递归解法需要剪枝. 剪枝1:s1,s2不等长return 剪枝2:s1,s2字符不相同r…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

(Version 0.0) 作为一个小弱,这个题目是我第一次碰到三维的动态规划.在自己做的时候意识到了所谓的scramble实际上有两种可能的类型,一类是在较低层的节点进行的两个子节点的对调,这样的情况如果我们从第一层切分点,或者说从较高层的切分点看的话,s1和s2切分点左边的子串所包含的字符的种类个数应该完全一致,同样右边也是完全一致:另一类是在较高层切分点进行的互换,这样我们如果在同层来考察s1和s2的话,会发现s1的切分点左侧的char和s2的切分点右侧的char种类和每种char的数目一…

题意: 判断两个字符串是否互为Scramble字符串,而互为Scramble字符串的定义: 字符串看作是父节点,从字符串某一处切开,生成的两个子串分别是父串的左右子树,再对切开生成的两个子串继续切开,直到无法再切,此时生成为一棵二叉树.对二叉树的任一子树可任意交换其左右分支,如果S1可以通过交换变成S2,则S1,S2互为Scramble字符串. 思路: 对于分割后的子串,应有IsScramble(s1[0,i] , s2[0,i]) && IsSCramble(s1[i,length] ,…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

原题地址 两个字符串满足什么条件才称得上是scramble的呢? 如果s1和s2的长度等于1,显然只有s1=s2时才是scramble关系. 如果s1和s2的长度大于1,那么就对s1和s2进行分割,划分成两个子问题分别处理. 如何分割呢?当然不能任意分割.假设分割后s1变成了s11和s12,s2变成了s21和s22,那么只有2种分割方式: 1. s11.length = s21.length & s12.length = s22.length,如下图所示: s1: ? ? ? ? ? -----…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

将一个单词按照这种方式分: Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may choose any non-leaf node and swap its two children. For example, if we choose the node "gr" an…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

题目链接 题目要求: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string…

原题地址:https://oj.leetcode.com/problems/scramble-string/ 题意: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

原题链接: http://oj.leetcode.com/problems/scramble-string/  这道题看起来是比較复杂的,假设用brute force,每次做分割,然后递归求解,是一个非多项式的复杂度,一般来说这不是面试官想要的答案. 这事实上是一道三维动态规划的题目,我们提出维护量res[i][j][n],当中i是s1的起始字符,j是s2的起始字符,而n是当前的字符串长度,res[i][j][len]表示的是以i和j分别为s1和s2起点的长度为len的字符串是不是互为scram…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 ="great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may cho…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…